Submission #23374

#	Time	Username	Problem	Language	Result	Execution time	Memory
23374		rubabredwan	ICC (CEOI16_icc)	C++14	0 / 100	363 ms	2136 KiB

icc

/* Bismillahir Rahmanir Rahim */

#include <bits/stdc++.h>
#include "icc.h"

using namespace std;

const int N = 105;

int n, par[N], mat[N][N];
set<int>comp;
vector<int>nudes[N];

int Find(int at){
    return par[at] == at ? at : par[at] = Find(par[at]);
}

void Union(int a, int b){
    int x = Find(a);
    int y = Find(b);
    for(auto u : nudes[y]){
        nudes[x].push_back(u);
    }
    par[y] = x;
    comp.erase(y);
}

// void setRoad(int a, int b){
//     if(a) Union(a, b);
//     int x, y;
//     cin >> x >> y;
//     mat[x][y] = 1;
//     mat[y][x] = 1;
// }

// int query(int sa, int sb, int a[], int b[]){
//     for(int i=0;i<sa;i++){
//         for(int j=0;j<sb;j++){
//             if(mat[a[i]][b[j]]) return true;
//         }
//     }
//     return false;
// }

int fuk[N], tt;

int get(int sa, int sb, int a[], int b[]){
    int lo = 0, hi = sb - 1;
    while(lo < hi){
        int mid = (lo + hi) / 2; tt = 0;
        for(int i=lo;i<=mid;i++) fuk[tt] = b[i], ++tt;
        if(query(sa, tt, a, fuk)) hi = mid;
        else lo = mid + 1;
    }
    return b[lo];
}

int aa[N], bb[N];

void run(int _n){
    n = _n;
    comp.clear();
    for(int i=1;i<=n;i++){
        par[i] = i;
        comp.insert(i);
        nudes[i].clear();
        nudes[i].push_back(i);
    }
    int road = n - 1;
    while(road--){
        while(1){
            int sa = 0, sb = 0;
            for(auto u : comp){
                if(rand() & 1){
                    for(auto v : nudes[u]){
                        aa[sa] = v;
                        ++sa;
                    }
                }
                else{
                    for(auto v : nudes[u]){
                        bb[sb] = v;
                        ++sb;
                    }
                }
            }
            if(query(sa, sb, aa, bb)){
                Union(get(sa, sb, aa, bb), get(sb, sa, bb, aa));
                break;
            }
        }
    }
}

• Subtask 1: 0 / 7
• Subtask 2: 0 / 11
• Subtask 3: 0 / 22
• Subtask 4: 0 / 21
• Subtask 5: 0 / 29
• Subtask 6: 0 / 10