Submission #233275

#	Time	Username	Problem	Language	Result	Execution time	Memory
233275		Vimmer	Segway (COI19_segway)	C++14	0 / 100	5 ms	384 KiB

segway

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
//#pragma GCC optimize("Ofast")

#define sz(x) ll(x.size())
#define N 20015
#define base 1000000
#define M ll(1e9+7)
#define F first
#define S second
#define pb push_back
#define in insert
#define eb emplace_back
#define ed "\n"

using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
typedef long double ld;
typedef short int si;

typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;


ordered_set se;

int main()
{
  //  freopen("input.txt","r",stdin); freopen("output.txt","w",stdout);

    ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0);

    int n;

    cin >> n;

    int a[n], b[n], c[n];

    for (int i = 0; i < n; i++) cin >> a[i] >> b[i] >> c[i];

    int m;

    cin >> m;

    if (m == 0)
    {
        for (int i = 0; i < n; i++) cout << (a[i] + b[i] + c[i]) * 100 << endl;

        exit(0);
    }
    else
    {
        int t;

        cin >> t;

        int when[n];

        for (int i = 0; i < n; i++)
        {
            if (t <= 100) when[i] = t * a[i];
              else if (t <= 200) when[i] = 100 * a[i] + (t - 100) * b[i];
                else when[i] = 100 * (a[i] + b[i]) + (t - 200) * c[i];

            se.insert(when[i]);
        }

        //for (auto it : se) cout << it << endl;

       // cout << endl;

        //cout << endl;
        for (int i = 0; i < n; i++)
        {
            int tp = se.order_of_key(when[i]);

            int ans = when[i] + min(tp, 300 - t);

            int tr = t + tp;

            if (tr <= 100) ans += (b[i] + c[i]) * 100 + a[i] * (100 - tr);
              else if (tr <= 200) ans += c[i] * 100 + b[i] * (200 - tr);
                else if (tr <= 300) ans += c[i] * (300 - tr);

           // cout << when[i] << " ";

            cout << ans << '\n';
        }
    }
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 40
• Subtask 3: 0 / 45