This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
/**
* author: Mohamad Milhem
* created: 2020-05-13-05.41.20
**/
#include "shoes.h"
#include <bits/stdc++.h>
#include <stdio.h>
using namespace std;
typedef long long ll;
#define FAST ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define mp make_pair
#define pb push_back
#define lp(i,s,f) for(ll i = s; i < ll(f); i++)
#define inF freopen("input.in", "r", stdin);
#define outF freopen("output.in", "w", stdout);
#define MOD ll(1000000007)
#define debug(x) cout << '[' << #x << " is: " << x << "] " <<endl;
#define decimalpoint cout << std::fixed << setprecision(5)
map<int,map<int,bool>> need;
int bro[200005];
int nothing[200005];
int seg[800005];
void update(int p , int s, int e, int i){
if (s == e){
seg[p] = 1;
return;
}
if (i <= (s+e)/2) update(p*2 , s , (s+e)/2 , i);
else update(p*2 + 1 , (s+e)/2 + 1 , e , i);
seg[p] = seg[p*2] + seg[p*2 + 1];
}
ll gett(int p , int s , int e , int a , int b){
if ((s >= a)&&(e <= b)){
return seg[p];
}
if ((s > b)||(a > e)){
return 0;
}
return gett(p*2 , s , (s+e)/2 , a , b) + gett(p*2 + 1 , (s+e)/2 + 1 , e , a , b);
}
long long count_swaps(std::vector<int> v) {
ll n = v.size();
need.clear();
memset(bro, 0 , sizeof bro);
memset(nothing , 0 , sizeof nothing);
memset(seg , 0 , sizeof seg);
for (int i = 0 ; i < n ; i++){
int needed = v[i]*-1;
auto here = need[needed].begin();
if (here == need[needed].end()){
need[v[i]][i] = true;
}
else {
int first = here->first;
int second = i;
bro[first] = second;
need[needed].erase(first);
}
}
ll ans = 0;
// for (auto a : bro){
// cout << a.first << " " << a.second << endl;
// }
for (ll i = 0 ; i < n ; i++){
ll now = v[i];
if (bro[i] == 0)continue;
ll cont = 0;
// for (ll j = i + 1 ; j < bro[i] ; j++){
//// if (nothing[j])cont++;
// }
cont = gett(1 , 0 , n - 1 , i + 1 , bro[i] - 1);
// debug(cont);
// debug(i);
// nothing[bro[i]] = 1;
update(1 , 0, n - 1 , bro[i]);
int leftt = (now < 0);
ll here = bro[i] - i - leftt - cont;
// debug(i);
// debug(here);
ans+= here;
}
return ans;
}
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