Submission #231160

#	Time	Username	Problem	Language	Result	Execution time	Memory
231160		infinite_iq	K blocks (IZhO14_blocks)	C++14	0 / 100	89 ms	4984 KiB

blocks

#define fast ios_base::sync_with_stdio(0),cin.tie(0),cout.tie(0)
#include <bits/stdc++.h>
using namespace std;
#define sqr 547
//#define mp make_pair
#define mid (l+r)/2
#define pb push_back
#define ppb pop_back
#define fi first
#define se second
#define lb lower_bound
#define ub upper_bound
#define ins insert
#define era erase
#define C continue
#define mem(dp,i) memset(dp,i,sizeof(dp))
#define mset multiset
#define all(x) x.begin(), x.end()
typedef long long ll;
typedef short int si;
typedef long double ld;
typedef pair<int,int> pi;
typedef pair<ll,ll> pll;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<pi> vpi;
typedef vector<pll> vpll;
const ll inf=1e18;
const ll mod=1e9+7;
const ld pai=acos(-1);
int n , k ;
int a [100009] , last [100009] , dp [100009][109] ;
int tree [400009][2] ;
void updRmq ( int node , int l , int r , int id , int val ){
    if ( l == r ) {
        tree [node][0] = tree [node][1] = val ;
        return ;
    }
    if ( id <= mid ) updRmq(node*2,l,mid,id,val);
    else updRmq(node*2+1,mid+1,r,id,val);
    tree [node][0] = min ( tree[node*2][0] , tree[node*2+1][0] ) ;
    tree [node][1] = max ( tree[node*2][1] , tree[node*2+1][1] ) ;
}
int queryRmq ( int node, int l , int r , int s , int e , int t ) {
    if ( l > r || s > r || e < l ) {
        if (!t) return 1e9 ;
        return 0 ;
    }
    if ( s <=l && e >= r ) return tree [node][t] ;
    return min ( queryRmq ( node*2 , l , mid , s , e , t ) , queryRmq ( node*2+1 , mid +1 , r , s , e , t ) ) ;
}
int main () {
    cin >> n >> k ;
    for ( int i = 1 ; i <= n ; i ++ ) cin >> a[i] , updRmq ( 1 , 0 , n , i , a[i] ) ;
    for ( int i = 1 ; i <= n ; i ++ ) {
        int l = 0 , r = i;
        while ( r - l > 1 ) {
            if ( queryRmq ( 1 , 0 , n , mid , i , 1 ) > a[i] ) l = mid ;
            else r = mid ;
        }
        last [i] = l ;
    }
    updRmq ( 1 , 0 , n , 0 , 1e9 ) ;
    for ( int i = 1 ; i <= n ; i ++ ) {
        dp [i][1] = max ( dp [i-1][1] , a[i] ) ;
        updRmq ( 1 , 0 , n , i , dp [i][1] ) ;
    }
    for ( int i = 0 ; i <= n ; i ++ ) {
        for ( int j = 2 ; j <= k ; j ++ ) {
            dp [i][j] = 1e9 ;
        }
    }
    for ( int j = 2 ; j <= k ; j ++ ) {
        for ( int i = j ; i <= n ; i ++ ) {
            int val1 = queryRmq ( 1 , 0 , n , last[i] , i-1 , 0 ) + a[i] ;
            int val2 = dp [last[i]][j] ;
            dp [i][j] = min (val1 , val2 );
        }
        for ( int i =1 ; i <= n ; i ++ ) {
            updRmq ( 1 , 0 , n , i , dp[i][j] ) ;
        }
    }
    cout << dp[n][k] << endl ;
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 18
• Subtask 3: 0 / 21
• Subtask 4: 0 / 47