# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
230928 | kym | List of Unique Integers (FXCUP4_unique) | C++17 | 5 ms | 512 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#ifndef LOCAL
#include "unique.h"
#endif
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
using namespace std;
#define FOR(i,s,e) for(ll i = s; i <= (ll)e; ++i)
#define DEC(i,s,e) for(ll i = s; i >= (ll)e; --i)
#define IAMSPEED ios_base::sync_with_stdio(false); cin.tie(0);
#define db(x) cerr << #x << "=" << x << "\n"
#define db2(x, y) cerr << #x << "=" << x << " , " << #y << "=" << y << "\n"
#define db3(a,b,c) cerr<<#a<<"="<<a<<","<<#b<<"="<<b<<","<<#c<<"="<<c<<"\n"
#define dbv(v) cerr << #v << ":"; for (auto ite : v) cerr << ite << ' '; cerr <<"\n"
#define dbvp(v) cerr << #v << ":"; for (auto ite : v) cerr << "{" << ite.f << ',' << ite.s << "} "; cerr << "\n"
#define dba(a,ss,ee) cerr << #a << ":"; FOR(ite,ss,ee) cerr << a[ite] << ' '; cerr << "\n"
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
#define ll long long
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define f first
#define s second
#define reach cerr << "LINE: " << __LINE__ << "\n";
typedef pair <ll, ll> pi;
typedef tuple<ll,ll,ll> ti3;
string cts(char x) {string t(1,x); return t;}
ll rand(ll a, ll b) { return a + rng() % (b-a+1); }
const int MOD = 1e9 + 7;
const int inf = (int)1e9 + 500;
const long long oo = (ll)1e18 + 500;
template <typename T> void chmax(T& a, T b) { a = max(a, b); }
template <typename T> void chmin(T& a, T b) { a = min(a, b); }
const int MAXN = -1;
#ifndef LOCAL
#define cerr if(0)cout
#endif
int lf[205],rg[205];
int UniqueCount(int R, int C);
vector<int> PickUnique(int n) {
lf[0]=1;
rg[n-1]=1;
FOR(i,1,n-1)lf[i]=UniqueCount(0,i);
DEC(i,n-2,0)rg[i]=UniqueCount(i,n-1);
//dba(lf,0,n-1);
//dba(rg,0,n-1);
vector<int>v;
FOR(i,0,n-1) {
if(i==0){
if(rg[0]<=rg[1])v.pb(0);
else v.pb(1);
} else if(i==n-1) {
if(lf[n-1]<=lf[n-2])v.pb(0);
else v.pb(1);
} else {
if(lf[i]<=lf[i-1] || rg[i]<=rg[i+1])v.pb(0);
else v.pb(1);
}
}
//dbv(v);
return v;
}
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