Submission #230137

#	Time	Username	Problem	Language	Result	Execution time	Memory
230137		xiaowuc1	Walk (POI13_spa)	C++14	0 / 100	5085 ms	257176 KiB

spa

#include <algorithm>
#include <bitset>
#include <cassert>
#include <chrono>
#include <complex>
#include <cstring>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <unordered_set>
#include <vector>

using namespace std;

// BEGIN NO SAD
#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define trav(a, x) for(auto& a : x)
#define all(x) x.begin(), x.end()
#define sz(x) (int)(x).size()
#define derr if(1) cerr
typedef vector<int> vi;
// END NO SAD

typedef long long ll;
typedef pair<int, int> pii;
typedef vector<vector<ll>> matrix;

typedef pair<int, pii> state;

ll parse() {
  string s;
  cin >> s;
  ll ret = 0;
  for(int i = 0; i < sz(s); i++) {
    ret <<= 1;
    ret |= s[i] == '1';
  }
  return ret;
}
vector<ll> bad;
int n, k;
bool finite(ll src, ll snk) {
  unordered_set<ll> s;
  vector<ll> all;
  all.reserve(n*k+n+1);
  all.push_back(src);
  s.insert(src);
  for(int i = 0; i < sz(all) && sz(all) <= n*k; i++) {
    for(int j = 0; j < n; j++) {
      ll curr = all[i] ^ (1LL << j);
      if(s.count(curr)) continue;
      auto it = lower_bound(all(bad), curr);
      if(it != bad.end() && *it == curr) continue;
      s.insert(curr);
      all.push_back(curr);
    }
  }
  return !s.count(snk) && sz(all) <= n*k;
}
void solve() {
  cin >> n >> k;
  ll src = parse();
  ll snk = parse();
  bad.reserve(k);
  for(int i = 0; i < k; i++) {
    bad.push_back(parse());
  }
  if(finite(src, snk) || finite(snk, src)) cout << "NIE\n";
  else cout << "TAK\n";
}
// are there edge cases (N=1?)
// are array sizes proper (scaled by proper constant, for example 2* for koosaga tree)
// integer overflow?
// DS reset properly between test cases

int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL); cout.tie(NULL);
  solve();
}

• Subtask 1: 0 / 12
• Subtask 2: 0 / 12
• Subtask 3: 0 / 12
• Subtask 4: 0 / 12
• Subtask 5: 0 / 13
• Subtask 6: 0 / 13
• Subtask 7: 0 / 13
• Subtask 8: 0 / 13