Submission #228259

#	Time	Username	Problem	Language	Result	Execution time	Memory
228259		Vimmer	Teoretičar (COCI18_teoreticar)	C++14	0 / 130	10684 ms	262148 KiB

teoreticar

#include <bits/stdc++.h>

//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("fast-math")
//#pragma GCC optimize("no-stack-protector")

#define F first
#define S second
#define sz(x) int(x.size())
#define pb push_back
#define N 100005
#define M ll(1e9 + 7)

using namespace std;

typedef long double ld;

typedef long long ll;

typedef short int si;



int ans[N * 5], cnt, kol[N * 2];

bool mk[N * 5];

vector <pair <int, int> > g[N * 2];

pair <int, int> gr[N * 5];

void dfs(int v, bool f, vector <int> &a, vector <int> &b)
{
    while (sz(g[v]))
    {
        pair <int, int> pt = g[v].back(); g[v].pop_back();

        if (mk[pt.S]) continue;

        mk[pt.S] = 1;

        kol[v]--; kol[pt.F]--;

        if (f) a.pb(pt.S); else b.pb(pt.S);

        dfs(pt.F, !f, a, b);

        break;
    }
}

void solve(vector <int> &cur)
{
    vector <int> vert; vert.clear();

    bool gd = 1;

    for (auto it : cur)
    {
        mk[it] = 0;

        int a = gr[it].F, b = gr[it].S;

        kol[a]++; kol[b]++;

        if (kol[a] == 1) vert.pb(a); else gd = 0;

        if (kol[b] == 1) vert.pb(b); else gd = 0;

        g[a].pb({b, it});

        g[b].pb({a, it});
    }

    if (gd)
    {
        cnt++;

        for (auto it : cur)
        {
            int a = gr[it].F, b = gr[it].S;

            kol[a]--; kol[b]--;

            g[a].clear(); g[b].clear();

            ans[it] = cnt;
        }

        return;
    }

    vector <int> a, b; a.clear(); b.clear();

    for (auto it : vert) if (kol[it] % 2 == 0) dfs(it, 0, a, b);

    for (auto it : vert) while (kol[it])  dfs(it, 0, a, b);

    solve(a);

    solve(b);
}

int main()
{
    //freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout);

    ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0);

    int n, m, k;

    cin >> n >> m >> k;

    vector <int> cur; cur.clear();

    for (int i = 0; i < k; i++)
    {
        int a, b;

        cin >> a >> b;

        gr[i] = {a, n + b};

        cur.pb(i);
    }

    solve(cur);

    cout << cnt << '\n';

    for (int i = 0; i < k; i++) cout << ans[i] << '\n';
}

• Subtask 1: 0 / 13
• Subtask 2: 0 / 13
• Subtask 3: 0 / 13
• Subtask 4: 0 / 13
• Subtask 5: 0 / 13
• Subtask 6: 0 / 13
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• Subtask 10: 0 / 13