Submission #226872

#	Time	Username	Problem	Language	Result	Execution time	Memory
226872		MetB	Cop and Robber (BOI14_coprobber)	C++14	100 / 100	887 ms	32248 KiB

coprobber

#include "coprobber.h"
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
 
using namespace __gnu_pbds;
 
#define N 1000003
 
using namespace std;
 
typedef long long ll;
typedef unsigned long long ull;
 
const ll INF = 1e18, MOD = 1e9 + 7, MOD2 = 1e6 + 3;

int d[N], dg[N], m, n;
int mv[N], gl, sm[500];
bool a[500][500];

vector <int> g[N];

int couple (int x, int y, int t) {
	return 2 * (x * n + y) + t;
}

tuple <int, int, int> decouple (int s) {
	return tuple <int, int, int> ((s / 2) / n, (s / 2) % n, s % 2);
}

void print (int s) {
	cout << (s / 2) / n << ' ' << (s / 2) % n << ' ' << s % 2 << endl;
}

bool is_n (int x, int y, int t, int i) {
	if (t) return a[x][i] || (x == i);
	return a[y][i];
}

int start (int v, bool A[][500]) {
	n = v;
	m = 2 * n * n;

	for (int i = 0; i < n; i++)
		for (int j = 0; j < n; j++)
			sm[i] += (int) A[i][j];
	memcpy (a, A, sizeof (a));

	for (int i = 0; i < n; i++)
		for (int j = 0; j < n; j++) {
			dg[couple (i, j, 0)] = sm[i] + 1;
			dg[couple (i, j, 1)] = sm[j];
		}

	fill (d, d + m, 2);

	queue <int> q;


	for (int i = 0; i < n; i++) {
		int s = couple (i, i, 0);
		d[s] = 1, d[s + 1] = 0;
		q.push (s), q.push (s + 1);
	}

	while (!q.empty ()) {
		int s = q.front ();
		int x, y, t;
		tie (x, y, t) = decouple (s);
		q.pop ();
		for (int i = 0; i < n; i++) {
			if (is_n (x, y, t, i)) {
				int to;
				if (t) to = couple (i, y, 0);
				else to = couple (x, i, 1);
				if (d[to] != 2) continue;
				if (!d[s]) {
					d[to] = 1, mv[to] = s;
					q.push (to);
				} else {
					if (--dg[to] < 1) {
						d[to] = 0;
						q.push (to);
					}
				}
			}
		}
	}

	for (int i = 0; i < n; i++) {
		int ok = 1;
		for (int j = 0; j < n; j++) {
			if (d[couple (i, j, 0)] != 1) {
				ok = 0; break;
			}
		}
		if (ok) return gl = i;
	}
	return -1;
}

int nextMove (int x) {
	int s = couple (gl, x, 0);
	s = mv[s];
	gl = (s / 2) / n;
	return gl;
}

• Subtask 1: 16 / 16
• Subtask 2: 14 / 14
• Subtask 3: 30 / 30
• Subtask 4: 40 / 40