# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
22667 | past future present (#40) | Unifying Values (KRIII5_UV) | C++14 | 356 ms | 2452 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <cstdio>
#include <algorithm>
#include <vector>
using namespace std;
typedef long long ll;
const ll mod = 1000000007;
int n;
ll a[10101];
ll sum[101010];
ll ans;
ll p[10101];
ll pow2(int x){
ll t = 2;
ll r = 1;
while(x){
if(x&1){
r = (r*t)%mod;
}
t = (t*t)%mod;
x>>=1;
}
return r;
}
int main(){
scanf("%d",&n);
for(int i=1;i<=n;i++){
scanf("%lld",&a[i]);
sum[i] = sum[i-1] + a[i];
}
for(int i=1;i<n;i++){
ll x = sum[i];
if(x==0){
int c = 0;
if(sum[n]!=0)continue;
for(int j=i+1;j<n;j++){
if(sum[j]==0)c++;
}
ans+=pow2(c);
ans%=mod;
continue;
}
if(sum[n]%x != 0)continue;
ll mx = sum[n]/x;
if(mx <=1)continue;
if(mx > n)continue;
vector<ll> v;
v.push_back(1);
for(int j=i+1;j<n;j++){
if(sum[j]%x == 0){
ll t = sum[j]/x;
if(t > 1 && t < mx)v.push_back(t);
}
}
v.push_back(mx);
fill(p,p+n+1,0);
p[0]=1;
for(auto t : v){
p[t]+=p[t-1];
p[t]%=mod;
}
ans+=p[v.back()];
ans%=mod;
}
printf("%lld\n",ans);
}
Compilation message (stderr)
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