답안 #22599

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
22599 2017-04-30T05:50:47 Z AcornCkiGs14004Team(#953, gs14004, cki86201, dotorya) Logistical Metropolis (KRIII5_LM) C++11
0 / 7
2000 ms 1048576 KB
#include <cstdio>
#include <algorithm>
#include <vector>
using namespace std;
typedef pair<int, int> pi;
typedef long long lint;
typedef long long int lli;

const int maxd = 21;
const int maxn = 100000 + 10;
const int INF = 0x3f3f3f3f;

struct Node {
	int x, y, w, k, id;
	void init(int tx, int ty, int tw, int i) {
		id = i;
		x = tx;
		y = ty;
		w = tw;
	}
	bool operator<(const Node& rhs) const { return w < rhs.w; }
} A[maxd][300001];

struct Modify {
	int k, d;
	void init(int tk, int td) {
		k = tk;
		d = td;
	 }
} B[1200003];
lint pr[1200005];
int cnt;

struct UnionFindSet {
	int pa[maxn];
	void init(int n) {
		for (int i = 1; i <= n; i++) pa[i] = i;
	}
	int find(int x) { return x == pa[x] ? x : (pa[x] = find(pa[x])); }
} ufs;

struct CDQ {
	int pa[maxn], dis[300005], pos[300005];

	void init(int m) {
		for (int i = 1; i <= m; i++) dis[A[0][i].id] = A[0][i].w;
	}

	// cur depth : d
	// modify sequence : [L, R]
	// points : n, edges : m
	void solve(int d, int L, int R, int n, int m, lli ans = 0LL) {
		for (int i = 1; i <= m; i++) {
			Node &a = A[d][i], &a2 = A[d - 1][i];
			a = (Node){a2.x, a2.y, dis[a2.id], 0, a2.id};
			pos[a.id] = i;
		}
		if (L == R) {
			Modify& b = B[L];
			A[d][pos[b.k]].w = dis[b.k] = b.d;
			ufs.init(n);
			sort(A[d] + 1, A[d] + m + 1);
			for (int i = 1; i <= m; i++) {
				Node& a = A[d][i];
				int x = ufs.find(a.x), y = ufs.find(a.y);
				if (x != y) {
					ufs.pa[y] = x;
					ans = ans + a.w;
				}
			}
			cnt++;
			if(pr[cnt]) printf("%lld\n", ans + pr[cnt]);
			return;
		}

		// reduction
		for (int i = L; i <= R; i++) A[d][pos[B[i].k]].k = 1;  // tag of in {S}
	ufs.init(n);
	sort(A[d] + 1, A[d] + m + 1);
	for (int i = 1; i <= m; i++)
		if (A[d][i].k == 0) {
			Node& a = A[d][i];
			int x = ufs.find(a.x), y = ufs.find(a.y);
			if (x != y) {
				ufs.pa[y] = x;
				a.k = 2;  // tag of in {T}
			}
		}

	// contraction
	for (int i = 1; i <= m; i++)
		if (A[d][i].k == 1) A[d][i].w = -INF;
	ufs.init(n);
	sort(A[d] + 1, A[d] + m + 1);
	for (int i = 1; i <= m; i++)
		if (A[d][i].k != 0) {
			Node& a = A[d][i];
			int x = ufs.find(a.x), y = ufs.find(a.y);
			if (x != y) {
				ufs.pa[y] = x;
				if (a.k != 1) a.k = 3;  // tag of in {T'-S}
			}
		}

	// rebuild
	ufs.init(n);
	for (int i = 1; i <= m; i++)
		if (A[d][i].k == 3) {
			Node& a = A[d][i];
			int x = ufs.find(a.x), y = ufs.find(a.y);
			ufs.pa[y] = x;
			ans = ans + a.w;
		}
	int newn = 0, newm = 0;
	for (int i = 1; i <= n; i++) pa[i] = 0;
	for (int i = 1; i <= n; i++) {
		int x = ufs.find(i);
		if (!pa[x]) pa[x] = ++newn;
	}
	for (int i = 1; i <= m; i++)
		if (A[d][i].k != 0) {
			Node& a = A[d][i];
			int x = ufs.find(a.x), y = ufs.find(a.y);
			if (x != y) A[d][++newm] = (Node){pa[x], pa[y], a.w, a.k, a.id};
		}

	int M = (L + R) >> 1;
	solve(d + 1, L, M, newn, newm, ans);
	solve(d + 1, M + 1, R, newn, newm, ans);
	}

} cdq;

vector<pi> gph[100005];

int main() {
	int n, m, q;
	scanf("%d %d", &n, &m);
	for(int i=1; i<=m; i++){
		int s, e, x;
		scanf("%d %d %d",&s,&e,&x);
		gph[s].push_back(pi(i, x));
		gph[e].push_back(pi(i, x));
		A[0][i].init(s, e, x, i);
	}
	q = 0;
	for(int i=1; i<=n; i++){
		lint s = 0;
		for(auto &j : gph[i]){
			B[++q].init(j.first, 0);
			s += j.second;
		}	
		pr[q] = s;
		for(auto &j : gph[i]){
			B[++q].init(j.first, j.second);
		}
	}
	cdq.init(m);
	cdq.solve(1, 1, q, n, m);
	return 0;
}


Compilation message

LM.cpp: In function 'int main()':
LM.cpp:138:24: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d %d", &n, &m);
                        ^
LM.cpp:141:29: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d %d %d",&s,&e,&x);
                             ^
# 결과 실행 시간 메모리 Grader output
1 Correct 46 ms 148576 KB Output is correct
2 Correct 43 ms 148576 KB Output is correct
3 Correct 43 ms 148576 KB Output is correct
4 Correct 46 ms 148576 KB Output is correct
5 Correct 46 ms 148576 KB Output is correct
6 Correct 43 ms 148576 KB Output is correct
7 Correct 46 ms 148576 KB Output is correct
8 Correct 39 ms 148576 KB Output is correct
9 Correct 43 ms 148576 KB Output is correct
10 Correct 43 ms 148576 KB Output is correct
11 Correct 43 ms 148576 KB Output is correct
12 Correct 43 ms 148576 KB Output is correct
13 Correct 43 ms 148576 KB Output is correct
14 Correct 43 ms 148576 KB Output is correct
15 Correct 43 ms 148576 KB Output is correct
16 Correct 39 ms 148576 KB Output is correct
17 Correct 39 ms 148576 KB Output is correct
18 Correct 39 ms 148576 KB Output is correct
19 Correct 39 ms 148576 KB Output is correct
20 Correct 43 ms 148576 KB Output is correct
21 Correct 39 ms 148576 KB Output is correct
22 Correct 39 ms 148576 KB Output is correct
23 Correct 39 ms 148576 KB Output is correct
24 Correct 43 ms 148576 KB Output is correct
25 Memory limit exceeded 119 ms 1048576 KB Memory limit exceeded
26 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 2000 ms 157288 KB Execution timed out
2 Halted 0 ms 0 KB -