Submission #22596

#TimeUsernameProblemLanguageResultExecution timeMemory
22596크리콘 B번 문제는 그리디로 풀려요 (#40)Unifying Values (KRIII5_UV)C++98
0 / 7
500 ms3732 KiB
#include<stdio.h>
#include<map>
#define ab(a) ((a)<0?-(a):(a))
using namespace std;

typedef long long lld;
const lld mod = 1000000007;

int N, scn;
lld ba[10101], sum[10101], dap;
map<pair<lld,int>, lld> dp;

lld dy(lld sm, int p){
	pair<lld,int> pp = make_pair(sm, p);
	if(p>N)return 1;
	if(dp.find(pp) != dp.end()) return dp[pp];
	lld dap=0;
	for(int i=p; i<=N; i++){
		if(sum[i]-sum[p-1] == sm) dap += dy(sm,i+1);
	}
	return dp[pp] = dap%mod;
}

int main(){
	scanf("%d", &N);
	for(int i=1; i<=N; i++){
		scanf("%lld", &ba[i]), sum[i]=sum[i-1]+ba[i];
	}
	for(int i=1; i<=N; i++){
		if(sum[N] == 0){
			if(sum[i] == 0) dap += dy(0, i+1);
		}
		else{
			if(sum[i] == 0)continue;
			if(ab(sum[N]) % ab(sum[i]))continue;
			if(sum[N] / sum[i] <= 0)continue;
			dap += dy(sum[i], i+1);
		}
	}
	printf("%lld", (dap+mod-1)%mod);
	return 0;
}

Compilation message (stderr)

UV.cpp: In function 'int main()':
UV.cpp:25:17: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d", &N);
                 ^
UV.cpp:27:47: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%lld", &ba[i]), sum[i]=sum[i-1]+ba[i];
                                               ^
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