Submission #225218

#	Time	Username	Problem	Language	Result	Execution time	Memory
225218		Vimmer	Mobitel (COCI19_mobitel)	C++14	91 / 130	6092 ms	13056 KiB

mobitel

#include <bits/stdc++.h>

//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("fast-math")
//#pragma GCC optimize("no-stack-protector")

#define F first
#define S second
#define sz(x) int(x.size())
#define pb push_back
#define N 200005
#define MOD ll(1e9 + 7)

using namespace std;

typedef long long ll;


ll dp[2][301][5000], a[301][301];

vector <ll> vr;

int opr(int x) {return upper_bound(vr.begin(), vr.end(), x) - vr.begin() - 1;}

int main()
{

    ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0);

    ll n, m, k;

    cin >> n >> m >> k;

    vr.pb(k);

    for (ll i = 1; i <= k; i++)
    {
        ll val = vr.back();

        while ((val - 1) * i >= k) val--;

        if (vr.back() != val) vr.pb(val);
    }

    vr.pb(1e18);

    sort(vr.begin(), vr.end());

    for (ll i = 0; i < n; i++)
        for (ll j = 0; j < m; j++) cin >> a[i][j];

   dp[0][0][opr(min(k, a[0][0]))] = 1;

    for (ll i = 0; i < n; i++)
        {
            for (ll j = 0; j < m; j++)
              for (ll u = 0; u < sz(vr) - 1; u++)
                {
                    if (dp[0][j][u] == 0) continue;

                    ll val = vr[u];

                    if (i + 1 != n) dp[1][j][opr(min(k, val * a[i + 1][j]))] = (dp[1][j][opr(min(k, val * a[i + 1][j]))] + dp[0][j][u]) % MOD;

                    if (j + 1 != m) dp[0][j + 1][opr(min(k, val * a[i][j + 1]))] = (dp[0][j + 1][opr(min(k, val * a[i][j + 1]))] + dp[0][j][u]) % MOD;
                }

            if (i + 1 != n)
            {
                for (ll j = 0; j < m; j++)
                  for (ll u = 0; u < sz(vr) - 1; u++) {dp[0][j][u] = dp[1][j][u]; dp[1][j][u] = 0;}
            }
        }

    cout << dp[0][m - 1][sz(vr) - 2];
}

• Subtask 1: 91 / 130