Submission #225206

#	Time	Username	Problem	Language	Result	Execution time	Memory
225206		Vimmer	Mobitel (COCI19_mobitel)	C++14	0 / 130	739 ms	65540 KiB

mobitel

#include <bits/stdc++.h>

//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("fast-math")
//#pragma GCC optimize("no-stack-protector")

#define F first
#define S second
#define sz(x) int(x.size())
#define pb push_back
#define N 200005
#define MOD ll(998244353)

using namespace std;

typedef long long ll;

typedef long double ld;


vector <pair <int, int> >  dp[301][301];
int  a[305][305];

int main()
{

    ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0);

    int n, m, k;

    cin >> n >> m >> k;

    if (k > 300) exit(0);

    for (int i = 0; i < n; i++)
        for (int j = 0; j < m; j++) cin >> a[i][j];

    dp[0][0].pb({1, a[0][0]});

    for (int i = 0; i < n; i++)
        for (int j = 0; j < m; j++)
          for (auto it : dp[i][j])
            {
                if (it.F == 0) continue;

                if (i + 1 != n)
                {
                    int val = it.S * a[i + 1][j];

                    val = min(val, k);

                    bool f = 0;

                    for (int u = 0; u < sz(dp[i + 1][j]); u++)
                      if (dp[i + 1][j][u].S == val) {f = 1; dp[i + 1][j][u].F = (dp[i + 1][j][u].F + it.F) % MOD; break;}

                    if (!f) dp[i + 1][j].pb({it.F, val});

                }

                if (j + 1 != m)
                {
                    int val = it.S * a[i][j + 1];

                    val = min(val, k);

                    bool f = 0;

                    for (int u = 0; u < sz(dp[i][j + 1]); u++)
                      if (dp[i][j + 1][u].S == val) {f = 1; dp[i][j + 1][u].F = (dp[i][j + 1][u].F + it.F) % MOD; break;}

                    if (!f) dp[i][j + 1].pb({it.F, val});

                }
            }

    int ans = 0;

    for (auto it : dp[n - 1][m - 1]) if (it.S == k)  ans = (ans + it.F) % MOD;

    cout << ans;
}

• Subtask 1: 0 / 130