Submission #225087

#TimeUsernameProblemLanguageResultExecution timeMemory
225087VimmerMobitel (COCI19_mobitel)C++14
0 / 130
332 ms65540 KiB
#include <bits/stdc++.h> //#pragma GCC optimize("unroll-loops") //#pragma GCC optimize("-O3") //#pragma GCC optimize("Ofast") //#pragma GCC optimize("fast-math") //#pragma GCC optimize("no-stack-protector") #define F first #define S second #define sz(x) int(x.size()) #define pb push_back #define N 100005 #define MOD ll(1e9 + 7) using namespace std; typedef long long ll; typedef long double ld; ll a[305][305], dp[305][305], f[305][305], n, m, s, ans; int mk[305][305]; vector <ll> g[305][305]; vector <pair <ll, ll> > vr; void dfs(int x, int y) { if (mk[x][y] == sz(vr)) return; mk[x][y] = sz(vr); g[x][y].pb(sz(vr) - 1); if (x + 1 != n && a[x + 1][y] == 1) dfs(x + 1, y); if (y + 1 != m && a[x][y + 1] == 1) dfs(x, y + 1); } void rec(int x, int y, ll sm, ll kol) { if (a[x][y] == 1) {vr.pb({sm, kol}); dfs(x, y); return;} if (sm >= s) {ans = (ans + (kol * dp[x][y]) % MOD) % MOD; return;} if (x + 1 != n) rec(x + 1, y, sm * a[x + 1][y], kol); if (y + 1 != m) rec(x, y + 1, sm * a[x][y + 1], kol); } int main() { ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> n >> m >> s; for (int i = 0; i < n; i++) for (int j = 0; j < m; j++) cin >> a[i][j]; dp[n - 1][m - 1] = 1; for (int i = n - 1; i >= 0; i--) for (int j = m - 1; j >= 0; j--) { if (i + 1 != n) dp[i][j] += dp[i + 1][j]; if (j + 1 != m) dp[i][j] += dp[i][j + 1]; dp[i][j] %= MOD; } for (int i = 0; i < n; i++) for (int j = 0; j < m; j++) { if (a[i][j] != 1) continue; if ((i == 0 || a[i - 1][j] != 1) && (j == 0 || a[i][j - 1] != 1)) f[i][j] = 1; else { if (i != 0 && a[i - 1][j] == 1) f[i][j] = (f[i - 1][j] + f[i][j]) % MOD; if (j != 0 && a[i][j - 1] == 1) f[i][j] = (f[i][j - 1] + f[i][j]) % MOD; } } rec(0, 0, a[0][0], 1); for (int i = 0; i < n; i++) for (int j = 0; j < m; j++) { if (a[i][j] != 1) continue; if (i + 1 != n && a[i + 1][j] != 1) for (auto it : g[i][j]) rec(i + 1, j, vr[it].F * a[i + 1][j], (vr[it].S * f[i][j]) % MOD); if (j + 1 != m && a[i][j + 1] != 1) for (auto it : g[i][j]) rec(i, j + 1, vr[it].F * a[i][j + 1], (vr[it].S * f[i][j]) % MOD); } cout << ans << endl; }
#Verdict Execution timeMemoryGrader output
Fetching results...