Submission #224978

#TimeUsernameProblemLanguageResultExecution timeMemory
224978T0p_Game (IOI13_game)C++14
100 / 100
3504 ms82424 KiB
#include "game.h" #define MAXR 1000000000 #define MAXC 1000000000 #include <assert.h> #include <stddef.h> long long gcd2(long long X, long long Y) { if(X == 0 || Y == 0) { return X + Y; } long long tmp; while (X != Y && Y != 0) { tmp = X; X = Y; Y = tmp % Y; } return X; } struct layer2_node { layer2_node(int low, int high) : low(low), high(high), lft(NULL), rht(NULL), value(0LL) { } int low; int high; layer2_node* lft; layer2_node* rht; long long value; }; struct layer1_node { layer1_node() : lft(NULL), rht(NULL), l2(0, MAXC) { } layer1_node* lft; layer1_node* rht; layer2_node l2; }; static layer1_node root; static void update2(layer2_node* node, int Q, long long K) { int low = node->low; int high = node->high; int mid = (low + high) / 2; if(low + 1 == high) { /* For leaf nodes we just update the value directly. */ node->value = K; return; } layer2_node*& tgt = Q < mid ? node->lft : node->rht; if(tgt == NULL) { /* If there is no node on this side of the tree create a new leaf node * containing exactly our update point. */ tgt = new layer2_node(Q, Q + 1); tgt->value = K; } else if(tgt->low <= Q && Q < tgt->high) { /* If the existing node contains our query point continue inserting there. */ update2(tgt, Q, K); } else { /* Otherwise traverse down the virtual tree until the side of our query node * and the side of the existing node differ. Create this node and continue * updating along it. */ do { (Q < mid ? high : low) = mid; mid = (low + high) / 2; } while((Q < mid) == (tgt->low < mid)); layer2_node* nnode = new layer2_node(low, high); (tgt->low < mid ? nnode->lft : nnode->rht) = tgt; tgt = nnode; update2(nnode, Q, K); } /* Internal nodes get updated as the gcd of its leaves. */ node->value = gcd2(node->lft ? node->lft->value : 0, node->rht ? node->rht->value : 0); } long long query2(layer2_node* nd, int A, int B) { /* The same as the level 1 queries except the interval each node represents * may skip some levels of the tree so we store them in the node itself. */ if(nd == NULL || B <= nd->low || nd->high <= A) { return 0; } else if(A <= nd->low && nd->high <= B) { return nd->value; } return gcd2(query2(nd->lft, A, B), query2(nd->rht, A, B)); } static void update1(layer1_node* node, int low, int high, int P, int Q, long long K) { int mid = (low + high) / 2; if(low + 1 == high) { update2(&node->l2, Q, K); } else { layer1_node*& nnode = P < mid ? node->lft : node->rht; (P < mid ? high : low) = mid; if(nnode == NULL) { nnode = new layer1_node(); } update1(nnode, low, high, P, Q, K); /* Compute what value to update with. */ K = gcd2(node->lft ? query2(&node->lft->l2, Q, Q + 1) : 0, node->rht ? query2(&node->rht->l2, Q, Q + 1) : 0); update2(&node->l2, Q, K); } } long long query1(layer1_node* nd, int low, int high, int A1, int B1, int A2, int B2) { /* Scan down the tree short-circuiting when we reach a node that contains * our entire query interval and combining the result of the level2 queries. */ if(nd == NULL || B1 <= low || high <= A1) { return 0; } else if(A1 <= low && high <= B1) { return query2(&nd->l2, A2, B2); } int mid = (low + high) / 2; return gcd2(query1(nd->lft, low, mid, A1, B1, A2, B2), query1(nd->rht, mid, high, A1, B1, A2, B2)); } void init(int R, int C) { } void update(int P, int Q, long long K) { update1(&root, 0, MAXR, P, Q, K); } long long calculate(int P, int Q, int U, int V) { return query1(&root, 0, MAXR, P, U + 1, Q, V + 1); }

Compilation message (stderr)

grader.c: In function 'int main()':
grader.c:18:6: warning: variable 'res' set but not used [-Wunused-but-set-variable]
  int res;
      ^~~
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