Submission #224631

#	Time	Username	Problem	Language	Result	Execution time	Memory
224631		infinite_iq	The Kingdom of JOIOI (JOI17_joioi)	C++14	0 / 100	231 ms	16248 KiB

joioi

#define fast ios_base::sync_with_stdio(0),cin.tie(0),cout.tie(0)
#include <bits/stdc++.h>
using namespace std;
#define sqr 547
#define mid (l+r)/2
#define pb push_back
#define ppb pop_back
#define fi first
#define se second
#define lb lower_bound
#define ub upper_bound
#define ins insert
#define era erase
#define C continue
#define mem(dp,i) memset(dp,i,sizeof(dp))
#define mset multiset
#define all(x) x.begin(), x.end()
typedef long long ll;
typedef short int si;
typedef long double ld;
typedef pair<int,int> pi;
typedef pair<ll,ll> pll;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<pi> vpi;
typedef vector<pll> vpll;
const ll inf=1e18;
const ll mod=1e9+7;
const ld pai=acos(-1);
int n , m ;
int a [2009][2009] , done [2009][2009] ;
int yes ( int x ) {
        int mn = 1e9 , mx = -1e9 ;
        for ( int i = 0 ; i < n ; i ++ ) {
                for ( int j = 0 ; j < m ; j ++ ) {
                        if ( done [i][j] ) C ;
                        mn = min ( mn , a [i][j] ) ;
                        mx = max ( mx , a [i][j] ) ;
                }
        }
        return ( mx - mn <= x ) ;
}
int check1 ( int x ) {
        mem ( done , 0 ) ;
        int last = 1e9 , mx = -1e9 , mn = 1e9 ;
        for ( int i = 0 ; i < n ; i ++ ) {
                int crnt = 0 ;
                for ( int j = 0 ; j < m ; j ++ ) {
                        if ( crnt == last ) break ;
                        int MN  = min ( mn , a [i][j] ) ;
                        int MX  = max ( mx , a [i][j] ) ;
                        if ( MX - MN > x ) {
                                last = crnt ;
                                break ;
                        }
                        mn = MN ;
                        mx = MX ;
                        crnt ++ ;
                        done [i][j] = 1 ;
                }
        }
        return yes ( x ) ;
}
int check2 ( int x ) {
        mem ( done , 0 ) ;
        int last = 1e9 , mx = -1e9 , mn = 1e9 ;
        for ( int i = n-1 ; i >=0 ; i -- ) {
                int crnt = 0 ;
                for ( int j = 0 ; j < m ; j ++ ) {
                        if ( crnt == last ) break ;
                        int MN = min ( mn , a [i][j] ) ;
                        int MX = max ( mx , a [i][j] ) ;
                        if ( MX - MN > x ) {
                                last = crnt ;
                                break ;
                        }
                        mn = MN ;
                        mx = MX ;
                        crnt ++ ;
                        done [i][j] = 1 ;
                }
        }
        return yes ( x ) ;
}
int check3 ( int x ) {
        mem ( done , 0 ) ;
        int last = 1e9 , mx = -1e9 , mn = 1e9 ;
        for ( int i = 0 ; i < n ; i ++ ) {
                int crnt = 0 ;
                for ( int j = m -1 ; j >= 0 ; j -- ) {
                        if ( crnt == last ) break ;
                        int MN = min ( mn , a [i][j] ) ;
                        int MX = max ( mx , a [i][j] ) ;
                        if ( MX - MN > x ) {
                                last = crnt ;
                                break ;
                        }
                        mn = MN ;
                        mx = MX ;
                        crnt ++ ;
                        done [i][j] = 1 ;
                }
        }
        return yes ( x )  ;
}
int check4 ( int x ) {
        mem ( done , 0 ) ;
        int last = 1e9 , mx = -1e9 , mn = 1e9 ;
        for ( int i = n-1 ; i >=0 ; i -- ) {
                int crnt = 0 ;
                for ( int j = m -1 ; j >= 0 ; j -- ) {
                        if ( crnt == last ) break ;
                        int MN = min ( mn , a [i][j] ) ;
                        int MX = max ( mx , a [i][j] ) ;
                        if ( MX - MN > x ) {
                                last = crnt ;
                                break ;
                        }
                        mn = MN ;
                        mx = MX ;
                        crnt ++ ;
                        done [i][j] = 1 ;
                }
        }
        return yes ( x )  ;
}
int main () {
        cin >> n >> m ;
        for ( int i = 0 ; i < n ; i ++ ) {
                for ( int j = 0 ; j < m ; j ++ ) {
                        cin >> a [i][j] ;
                }
        }
        int l = -1 , r = 2e9 ;
        while ( r - l > 1 ) {
                if ( check1 ( mid ) || check2 ( mid ) || check3 ( mid ) || check4 ( mid ) ) r = mid ;
                else l = mid ;
        }
        cout << r << endl ;
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 45
• Subtask 3: 0 / 40