| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 22209 | sgc109 (#42) | 구간들 (KRIII5P_3) | C++11 | 79 ms | 15284 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define REP(i,a,b) for(int i=a;i<=b;++i)
#define FOR(i,n) for(int i=0;i<n;++i)
#define pb push_back
#define all(v) (v).begin(),(v).end()
#define sz(v) ((int)(v).size())
#define inp1(a) scanf("%d",&a)
#define inp2(a,b) scanf("%d%d",&a,&b)
#define inp3(a,b,c) scanf("%d%d%d",&a,&b,&c)
#define inp4(a,b,c,d) scanf("%d%d%d%d",&a,&b,&c,&d)
#define inp5(a,b,c,d,e) scanf("%d%d%d%d%d",&a,&b,&c,&d,&e)
#define fastio() ios_base::sync_with_stdio(false),cin.tie(NULL)
using namespace std;
typedef long long ll;
typedef pair<ll,ll> pll;
typedef vector<int> vi;	
typedef vector<ll> vl;
typedef pair<int,int> pii;
typedef vector<pii> vii;
typedef vector<pll> vll;
typedef vector<vector<int> > vvi;
typedef pair<int,pair<int,int> > piii;
typedef vector<piii> viii;
const double EPSILON = 1e-9;
const double PI = acos(-1);
const int MOD = 1e9+7;
const int INF = 0x3c3c3c3c;
const long long INFL = 0x3c3c3c3c3c3c3c3c;
const int MAX_N = 102;
int N;
set<ll> st;
vll range;
vl comp;
ll t[800003];
ll pow2[100003];
int size;
vll v;
void update(int pos, int v){
	while(pos <= size){
		t[pos] += v;
		pos += pos&-pos;
	}
}
ll query(int pos){
	ll ret = 0;
	while(pos > 0){
		ret += t[pos];
		pos -= pos&-pos;
	}
	return ret;
}
bool cmp(pll& A, pll& B){
	if(A.second != B.second) return A.second < B.second;
	return A.first < B.first;
}
int main() {
	inp1(N);
	int cnt = 0;
	FOR(i,N){
		ll a,b;
		scanf("%lld%lld",&a,&b);
		if(a>=b) {
			cnt++;
			continue;
		}
		v.pb({a,1});
		v.pb({b,-1});
	}
	N-=cnt;
	sort(all(v));
	pow2[0] = 1;
	FOR(i,100001) pow2[i+1] = (pow2[i] * 2) % MOD;
	ll sum = 0;
	int on = 0;
	
	FOR(i,sz(v)){
		on += v[i].second;
		if(!on) continue;
		if(i!=sz(v)-1) sum = (sum + (v[i+1].first-v[i].first)*(pow2[on]-1)) % MOD;;
	}
	int prev = 0;
	int cur = 0;
	ll ans = 0;
	on = 0;
	FOR(i,sz(v)){
		on += v[i].second;
		if(v[i].second == 1 && (i == sz(v)-1 || v[i+1].second == -1)){
			cur++;
			ans = (ans + pow2[prev]*(pow2[cur]-1)) % MOD;
			prev += cur;
			cur = 0;
		}
		if(v[i].second == 1 && (i < sz(v)-1 && v[i+1].second == 1)) cur++;
		if(v[i].second == -1) prev--;
	}
	printf("%lld %lld",sum, ans);
	return 0;
}
Compilation message (stderr)
| # | Verdict | Execution time | Memory | Grader output | 
|---|---|---|---|---|
| Fetching results... | ||||
