Submission #221863

#	Time	Username	Problem	Language	Result	Execution time	Memory
221863		patrikpavic2	Candies (JOI18_candies)	C++17	8 / 100	1010 ms	167440 KiB

candies

#include <cstdio>
#include <vector>
#include <algorithm>

#define PB push_back
#define X first
#define Y second

using namespace std;

typedef long long ll;
typedef pair < int, int > pii;
typedef vector < ll > vi;

const int N = 3e5 + 500;

vi v[N][4];
int cnt = 0, n, A[N];

vi mrg(vi &A, vi &B){
	if(!A.size()) return B;
	if(!B.size()) return A;
	vi C = {A[0], B[0]};
	for(int i = 1;i < (int)A.size();i++)
		C.PB(A[i] - A[i - 1]);
	for(int i = 1;i < (int)B.size();i++)
		C.PB(B[i] - B[i - 1]);
	sort(C.rbegin(), C.rend());
	for(int i = 1;i < (int)C.size();i++)
		C[i] += C[i - 1];
	return C;
}

vi mks(vi A, vi B){
	if(A.size() < B.size()) swap(A, B);
	vi C = A;
	for(int i = 0;i < (int)B.size();i++)
		C[i] = max(C[i], B[i]);
	return C;
}

int solve(int l,int r){
	if(l == r){
		v[cnt][3].PB(A[l]);
		return cnt++;
	}
	int L = solve(l, (l + r) / 2);
	int R = solve((l + r) / 2 + 1, r);
	for(int i = 0;i < 4;i++){
		for(int j = 0;j < 4;j++){
			if((i&2) && (j&1)) continue;
			v[cnt][(i&1) + (j&2)] = mks(v[cnt][(i&1) + (j&2)], mrg(v[L][i], v[R][j]));
		}
	}
	return cnt++;	
}


int main(){
	scanf("%d", &n);
	for(int i = 0;i < n;i++)
		scanf("%d", A + i); 
	int kraj = solve(0, n - 1);
	vi fin = mks(mks(v[kraj][0], v[kraj][1]), mks(v[kraj][2], v[kraj][3]));
	for(ll x : fin) printf("%lld\n", x);
}

Compilation message (stderr)

candies.cpp: In function 'int main()':
candies.cpp:60:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d", &n);
  ~~~~~^~~~~~~~~~
candies.cpp:62:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d", A + i); 
   ~~~~~^~~~~~~~~~~~~

• Subtask 1: 8 / 8
• Subtask 2: 0 / 92