Submission #220005

#	Time	Username	Problem	Language	Result	Execution time	Memory
220005		Haunted_Cpp	Uzastopni (COCI15_uzastopni)	C++17	40 / 160	1099 ms	15028 KiB

uzastopni

#include <iostream>
#include <algorithm>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <queue>
#include <cassert>
#include <string>
#include <cstring>
#include <bitset>
#include <random>
#include <chrono>
#include <iomanip>
 
/*
#pragma GCC optimize ("Ofast")
#pragma GCC target("fma,sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native")
#pragma GCC optimize("unroll-loops")
*/
 
#define FOR(i, a, b) for(int i = a; i < (int) b; i++)
#define F0R(i, a) FOR (i, 0, a)
#define ROF(i, a, b) for(int i = a; i >= (int) b; i--)
#define R0F(i, a) ROF(i, a, 0)
#define GO(i, a) for (auto i : a)
 
#define rsz resize
#define eb emplace_back
#define pb push_back
#define sz(x) (int) x.size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define f first
#define s second
 
using namespace std;
 
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<pii> vpii;
typedef vector<vi> vvi;
typedef vector<vpii> vvpii;
typedef long long i64;
typedef vector<i64> vi64;
typedef vector<vi64> vvi64;
typedef pair<i64, i64> pi64;
typedef vector<pi64> vpi64;
 
const int dr[] = {+1, -1, +0, +0, +1, -1, +1, -1};
const int dc[] = {+0, +0, +1, -1, +1, -1, -1, +1};
const int ms[] = {+31, +29, +31, 30, +31, +30, +31, +31, +30, +31, +30, +31};
 
// It should something like -> O ( N * V ^ 3 ), 50 pts  
 
const int N = 1e4 + 1;
const int V = 1e2 + 1;
 
vvi g (N); 
 
// We are dealing with sets. No duplicates allowed. This is why bitset is correct.
bitset<V> dp [N][V];
bitset<V> Get [V];

int joke [N];

void dfs (int node = 0) {
  GO (to, g[node]) {
    dfs (to);
  }
  dp[node][joke[node]][joke[node]] = 1;
  F0R (i, V) Get[i].reset();
  GO (to, g[node]) {
    FOR (x, 1, V) {
      Get[x] = (Get[x] | dp[to][x]);
    }
  }
  for (int tamanho = 1; tamanho < V; tamanho++) {
    for (int L = 1; L + tamanho < V; L++) {
      const int R = L + tamanho; // Inclusive
      for (int k = L; k <= R / 2 + 5; k++) {
        bool ansA = (dp[node][L][k] & Get[k + 1][R]);
        bool ansB = (Get[L][k] & dp[node][k + 1][R]);  
        dp[node][L][R] = (dp[node][L][R] | ansA);
        dp[node][L][R] = (dp[node][L][R] | ansB);
        if (ansA || ansB) break;
      }
    }
  } 
}
 
int main () {
  ios::sync_with_stdio(0);
  cin.tie(0);
  int n;
  cin >> n;
  F0R (i, n) cin >> joke[i];
  F0R (i, n - 1) {
    int st, et;
    cin >> st >> et;
    --st; --et;
    g[st].eb(et);
  }
  dfs ();
  int res = 0;
  FOR (i, 1, V) res += dp[0][i].count();
  cout << res << '\n';
  return 0;
}

• Subtask 1: 40 / 160