Submission #213194

#	Time	Username	Problem	Language	Result	Execution time	Memory
213194		eriksuenderhauf	Constellation 3 (JOI20_constellation3)	C++11	35 / 100	1265 ms	524292 KiB

constellation3

//#pragma GCC optimize("O3")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define trav(x,a) for (const auto& x: a)
#define sz(x) (int)(x).size()
#define mem(a,v) memset((a), (v), sizeof (a))
#define enl printf("\n")
#define case(t) printf("Case #%d: ", (t))
#define ni(n) scanf("%d", &(n))
#define nl(n) scanf("%I64d", &(n))
#define nai(a, n) for (int _i = 0; _i < (n); _i++) ni(a[_i])
#define nal(a, n) for (int _i = 0; _i < (n); _i++) nl(a[_i])
#define pri(n) printf("%d\n", (n))
#define prl(n) printf("%I64d\n", (n))
#define pii pair<int, int>
#define pll pair<long long, long long>
#define vii vector<pii>
#define vll vector<pll>
#define vi vector<int>
#define vl vector<long long>
#define pb push_back
#define mp make_pair
#define st first
#define nd second
using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef cc_hash_table<int,int,hash<int>> ht;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> oset;
const double pi = acos(-1);
const int mod = 1e9 + 7;
const int inf = 1e9 + 7;
const int N = 1e6 + 5;
const double eps = 1e-9;

#define log2(x) (31 - __builtin_clz(x))

struct sparse_table {
  int n;
  vector<int> a;
  vector<vector<int>> st;
  int combine(int dl, int dr) {
    return a[dl] > a[dr] ? dl : dr;
  }
  sparse_table() {}
  sparse_table(vector<int> & a) : n(a.size()), a(a), st(log2(n) + 1, vector<int>(n)) {
    for (int i = 0; i < n; i++)
      st[0][i] = i;
    for (int j = 1; 1 << j <= n; j++)
      for (int i = 0; i + (1 << j) <= n; i++)
        st[j][i] = combine(st[j - 1][i], st[j - 1][i + (1 << (j - 1))]);
  }
  // query the data on the range [l, r[
  int query(int l, int r) {
    int s = log2(r - l);
    return combine(st[s][l], st[s][r - (1 << s)]);
  }
};

multiset<pll> stX[N];
ll dp1[N], dp2[N];

void join(int i, pll jj) {
  int j = jj.nd;
  if (j < 0) return;
  dp2[i] += jj.st;
  trav(x, stX[j])
    stX[i].insert({x.st, x.nd - dp1[j] + dp1[i]});
}

pll dfs(int l, int r, int i, sparse_table& s) {
  if (l > r) return {0, -1};
  int id = l;
  if (l != r) {
    id = s.query(l, r+1);
    int mx = s.a[id];
    join(id, dfs(l, id - 1, mx, s));
    join(id, dfs(id + 1, r, mx, s));
  }
  while (!stX[id].empty() && stX[id].begin()->st <= i) {
    dp1[id] = max(dp1[id], stX[id].begin()->nd);
    stX[id].erase(stX[id].begin());
  }
  return {dp1[id] + dp2[id], id};
}

int main() {
  int n; ni(n);
  vector<int> a(n+1);
  for (int i = 1; i <= n; i++) {
    scanf("%d", &a[i]);
  }
  int m; ni(m);
  ll ans = 0;
  for (int i = 1; i <= m; i++) {
    int x, y, c; scanf("%d %d %d", &x, &y, &c);
    stX[x].insert({y, c});
    ans += c;
  }
  sparse_table s(a);
  printf("%lld\n", ans - dfs(1, n, n+1, s).st);
  return 0;
}

Compilation message (stderr)

constellation3.cpp: In function 'int main()':
constellation3.cpp:10:20: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define ni(n) scanf("%d", &(n))
               ~~~~~^~~~~~~~~~~~
constellation3.cpp:89:10: note: in expansion of macro 'ni'
   int n; ni(n);
          ^~
constellation3.cpp:92:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d", &a[i]);
     ~~~~~^~~~~~~~~~~~~
constellation3.cpp:10:20: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define ni(n) scanf("%d", &(n))
               ~~~~~^~~~~~~~~~~~
constellation3.cpp:94:10: note: in expansion of macro 'ni'
   int m; ni(m);
          ^~
constellation3.cpp:97:23: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     int x, y, c; scanf("%d %d %d", &x, &y, &c);
                  ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 14 / 14
• Subtask 2: 21 / 21
• Subtask 3: 0 / 65