Submission #212131

#	Time	Username	Problem	Language	Result	Execution time	Memory
212131		NONAME	Nivelle (COCI20_nivelle)	C++17	0 / 110	37 ms	640 KiB

nivelle

#include <bits/stdc++.h>
#include <time.h>
#include <random>
#ifndef _LOCAL
#pragma GCC optimize("-O3")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#endif
#define sz(x) int(x.size())
#define in(x) freopen(x,"r",stdin)
#define out(x) freopen(x,"w",stdout)
#define N 100500
#define oo ll(1e16)
#define pii pair <int, int>
#define pll pair <ll, ll>
#define ft first
#define sd second
#define pb push_back
#define el '\n'
#define elf endl
#define base ll(1e9 + 7)
#define re return
#define nins 4294967295
using namespace std;
typedef long long ll;
typedef long double ld;
 
mt19937 rnd(0);
 
ll add(ll x, ll y, ll mod) {
    return (mod == 0) ? (x + y) : (x + y) % mod;
}
 
ll mul(ll x, ll y, ll mod) {
    return (mod == 0) ? (x * y) : (x * y) % ll(mod);
}
 
int n, res, l, r, f[26];
string s;
vector <pii> lst(26);
 
int main() {
    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    #ifdef _LOCAL
        in("input.txt");
        clock_t start_time = clock();
    #endif
 
    cin >> n;
    cin >> s;
 
    res = 1;
    l = r = 0;
 
    for (int i = 0; i < 26; i++)
        f[i] = -1, lst[i].ft = -1, lst[i].sd = i;
 
    for (int i = 0; i < n; i++) {
        int c = s[i] - 'a';
        if (f[c] != -1) continue;
        f[c] = i;
    }
 
    for (int i = 0; i < n; i++) {
        int c = s[i] - 'a';
 
        for (int j = 0; j < 26; j++)
            if (lst[j].sd == c)
                lst[j].ft = i;
 
        sort(lst.begin(), lst.end());
 
        for (int j = 0; j < 26; j++) {
            int x = lst[j].ft;
 
            if (x == -1) continue;
 
            if ((26 - j) * (r - l + 1) < res * (i - f[lst[j].sd] + 1)) {
                res = 26 - j;
                l = f[lst[j].sd];
                r = i;
            }
        }
    }
 
    cout << l + 1 << ' ' << r + 1;
 
	#ifdef _LOCAL
        cerr.precision(4); cerr << fixed;
        cerr << el;
        cerr << "Time :: " << ld(clock() - start_time) / CLOCKS_PER_SEC << el;
    #endif
}

• Subtask 1: 0 / 7
• Subtask 2: 0 / 17
• Subtask 3: 0 / 13
• Subtask 4: 0 / 25
• Subtask 5: 0 / 48