This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 110;
const int K = 10010;
const int oo = 2e9;
int a[N], f[2][N][K], n, l, r, k, ans[N][K], answ[N][K], res = oo;
int main(){
ios_base::sync_with_stdio(0); cin.tie(0);
// freopen("in.txt","r",stdin);
cin >> n >> l >> r >> k;
for (int i = 1; i <= n; i++)
cin >> a[i];
for (int i = 0; i < n + 2; i++)
fill(ans[i], ans[i] + k + 1, oo);
for (int j = l - 1; j <= r; j++)
for (int ost = 0; ost <= k; ost++)
f[0][j][ost] = oo;
f[0][l - 1][k] = 0;
for (int i = l; i <= r; i++)
f[0][l - 1][k] += a[i];
int sum = f[0][l - 1][k], it = 0;
for (int i = l; i > 0; i--, it ^= 1) {
for (int j = l - 1; j <= r; j++)
for (int ost = 0; ost <= k; ost++)
f[it ^ 1][j][ost] = oo;
for (int j = l - 1; j <= r; j++)
for (int ost = 0; ost <= k; ost++){
if (f[it][j][ost] == oo) continue;
ans[j][ost] = min(ans[j][ost], f[it][j][ost]);
if (i > 0)
f[it ^ 1][j][ost] = min(f[it ^ 1][j][ost], f[it][j][ost]);
if (j < r)
f[it][j + 1][ost] = min(f[it][j + 1][ost], f[it][j][ost]);
if (i > 0 && j < r) {
int n1 = i - 1, n2 = j + 1;
f[it ^ 1][n2][ost - (n2 - n1)] = min(f[it ^ 1][n2][ost - (n2 - n1)], f[it][j][ost] + a[n1] - a[n2]);
}
}
}
for (int ost = k; ost >= 0; ost--)
for (int i = l - 1; i <= r; i++){
if (i >= l)
ans[i][ost] = min(ans[i][ost], ans[i - 1][ost]);
if (ost >= 0)
ans[i][ost - 1] = min(ans[i][ost - 1], ans[i][ost]);
}
// right side
for (int i = 0; i < n + 2; i++)
fill(answ[i], answ[i] + k + 1, oo);
for (int j = r + 1; j >= l; j--)
for (int ost = 0; ost <= k; ost++)
f[0][j][ost] = oo;
it = 0;
f[0][r + 1][k] = 0;
for (int i = l; i <= r; i++)
f[0][r + 1][k] += a[i];
for (int i = r; i <= n; i++, it ^= 1){
for (int j = r + 1; j >= l; j--)
for (int ost = 0; ost <= k; ost++)
f[it ^ 1][j][ost] = oo;
for (int j = r + 1; j >= l; j--)
for (int ost = 0; ost <= k; ost++){
if (f[it][j][ost] == oo) continue;
answ[j][ost] = min(answ[j][ost], f[it][j][ost]);
if (i < n)
f[it ^ 1][j][ost] = min(f[it ^ 1][j][ost], f[it][j][ost]);
if (j > l)
f[it][j - 1][ost] = min(f[it][j - 1][ost], f[it][j][ost]);
if (i < n && j > l) {
int n1 = i + 1, n2 = j - 1;
f[it ^ 1][n2][ost - (n1 - n2)] = min(f[it ^ 1][n2][ost - (n1 - n2)], f[it][j][ost] + a[n1] - a[n2]);
}
}
}
for (int i = r + 1; i >= l; i--)
for (int ost = 0; ost <= k; ost++) {
if (i <= r)
answ[i][ost] = min(answ[i][ost], answ[i + 1][ost]);
int opp = k - ost;
if (ans[i - 1][opp] < oo && answ[i][ost] < oo)
res = min(res, ans[i - 1][opp] + answ[i][ost]);
}
cout << res - sum;
return 0;
}
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