Submission #212095

#	Time	Username	Problem	Language	Result	Execution time	Memory
212095		NONAME	Holding (COCI20_holding)	C++17	88 / 110	145 ms	262148 KiB

holding

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 110;
const int K = 10010;
const int oo = 2e9;
int a[N], f[N][N][K], n, l, r, k, ans[N][K], answ[N][K], res = oo;

int main(){
    
    ios_base::sync_with_stdio(0); cin.tie(0);
    
//    freopen("in.txt","r",stdin);

    cin >> n >> l >> r >> k;
        
    for (int i = 1; i <= n; i++)
        cin >> a[i];

    for (int i = 1; i <= n; i++)
        for (int j = 0; j <= n + 1; j++)
            for (int kl = 0; kl <= k; kl++)
                f[i][j][kl] = oo;
        
    for (int i = 0; i < n + 2; i++)
        fill(ans[i], ans[i] + k + 1, oo);
        
    f[l][l - 1][k] = 0;
    
    for (int i = l; i <= r; i++)
        f[l][l - 1][k] += a[i];
        
    for (int i = l; i > 0; i--)
        for (int j = l - 1; j <= r; j++)
            for (int ost = 0; ost <= k; ost++){
                if (f[i][j][ost] == oo) continue;
                
                ans[j][ost] = min(ans[j][ost], f[i][j][ost]);
                
                if (i > 0)
                    f[i - 1][j][ost] = min(f[i - 1][j][ost], f[i][j][ost]);
                
                if (j < r)
                    f[i][j + 1][ost] = min(f[i][j + 1][ost], f[i][j][ost]);
                
                if (i > 0 && j < r) {
                    int n1 = i - 1, n2 = j + 1;
                    f[n1][n2][ost - (n2 - n1)] = min(f[n1][n2][ost - (n2 - n1)], f[i][j][ost] + a[n1] - a[n2]);
                }
            }
    
    for (int ost = k; ost >= 0; ost--) 
        for (int i = l - 1; i <= r; i++){
            if (i >= l)
                ans[i][ost] = min(ans[i][ost], ans[i - 1][ost]);
            
            if (ost >= 0)
                ans[i][ost - 1] = min(ans[i][ost - 1], ans[i][ost]);
        }
    
    // right side
    
    for (int i = 0; i < n + 2; i++)
        fill(answ[i], answ[i] + k + 1, oo);
    
    for (int i = 1; i <= n; i++)
        for (int j = 0; j <= n + 1; j++)
            for (int kl = 0; kl <= k; kl++)
                f[i][j][kl] = oo;
        
    f[r][r + 1][k] = 0;
    
    for (int i = l; i <= r; i++)
        f[r][r + 1][k] += a[i];
        
    for (int i = r; i <= n; i++)
        for (int j = r + 1; j >= l; j--)
            for (int ost = 0; ost <= k; ost++){
                if (f[i][j][ost] == oo) continue;
                
                answ[j][ost] = min(answ[j][ost], f[i][j][ost]);
                
                if (i < n)
                    f[i + 1][j][ost] = min(f[i + 1][j][ost], f[i][j][ost]);
                
                if (j > l)
                    f[i][j - 1][ost] = min(f[i][j - 1][ost], f[i][j][ost]);
                
                if (i < n && j > l) {
                    int n1 = i + 1, n2 = j - 1;
                    f[n1][n2][ost - (n1 - n2)] = min(f[n1][n2][ost - (n1 - n2)], f[i][j][ost] + a[n1] - a[n2]);
                }
            }
    
    for (int i = r + 1; i >= l; i--)
        for (int ost = 0; ost <= k; ost++) {
            if (i <= r)
                answ[i][ost] = min(answ[i][ost], answ[i + 1][ost]);
            
            int opp = k - ost;
            
            if (ans[i - 1][opp] < oo && answ[i][ost] < oo) 
                res = min(res, ans[i - 1][opp] + answ[i][ost]);
        }
        
    cout << res - f[r][r + 1][k];
    
    return 0;
}

• Subtask 1: 22 / 22
• Subtask 2: 33 / 33
• Subtask 3: 33 / 33
• Subtask 4: 0 / 22