# |
Submission time |
Handle |
Problem |
Language |
Result |
Execution time |
Memory |
211886 |
2020-03-21T15:10:39 Z |
mode149256 |
Poi (IOI09_poi) |
C++14 |
|
303 ms |
16248 KB |
/*input
5 3 2
0 0 1
1 1 0
1 0 0
1 1 0
1 1 0
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
typedef pair<int, int> pi;
typedef pair<ll, ll> pl;
typedef pair<ld, ld> pd;
typedef vector<int> vi;
typedef vector<vi> vii;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<vl> vll;
typedef vector<pi> vpi;
typedef vector<vpi> vpii;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
typedef vector<pd> vpd;
typedef vector<bool> vb;
typedef vector<vb> vbb;
typedef std::string str;
typedef std::vector<str> vs;
#define x first
#define y second
#define debug(...) cout<<"["<<#__VA_ARGS__<<": "<<__VA_ARGS__<<"]\n"
const int MOD = 1000000007;
const ll INF = std::numeric_limits<ll>::max();
const int MX = 100101;
const ld PI = 3.14159265358979323846264338327950288419716939937510582097494L;
template<typename T>
pair<T, T> operator+(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x + b.x, a.y + b.y); }
template<typename T>
pair<T, T> operator-(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x - b.x, a.y - b.y); }
template<typename T>
T operator*(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.x + a.y * b.y); }
template<typename T>
T operator^(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.y - a.y * b.x); }
template<typename T>
void print(vector<T> vec, string name = "") {
cout << name;
for (auto u : vec)
cout << u << ' ';
cout << '\n';
}
struct ppl {
int sum;
int kiek;
int id;
};
int main() {
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
int N, T, P;
cin >> N >> T >> P;
vii sk(N, vi(T));
vi neis(T, 0);
for (int i = 0; i < N; ++i)
{
for (int j = 0; j < T; ++j)
{
cin >> sk[i][j];
neis[j] += !sk[i][j];
}
}
vector<ppl> people(N);
for (int i = 0; i < N; ++i)
{
auto &p = people[i];
p.id = i + 1;
p.sum = p.kiek = 0;
for (int j = 0; j < T; ++j)
{
if (sk[i][j]) {
p.kiek++;
p.sum += neis[j];
}
}
}
sort(people.begin(), people.end(), [](const ppl a, const ppl b) {
return a.sum > b.sum or (a.sum == b.sum and a.kiek > b.kiek) or
(a.sum == b.sum and a.kiek == b.kiek and a.id < b.id);
});
for (int i = 0; i < N; ++i)
{
if (people[i].id == P) {
printf("%d %d\n", people[i].sum, i + 1);
break;
}
}
}
/* Look for:
* special cases (n=1?)
* overflow (ll vs int?)
* the exact constraints (multiple sets are too slow for n=10^6 :( )
* array bounds
*/
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Correct |
5 ms |
384 KB |
Output is correct |
2 |
Correct |
5 ms |
384 KB |
Output is correct |
3 |
Correct |
5 ms |
384 KB |
Output is correct |
4 |
Correct |
5 ms |
384 KB |
Output is correct |
5 |
Correct |
5 ms |
384 KB |
Output is correct |
6 |
Correct |
5 ms |
384 KB |
Output is correct |
7 |
Correct |
5 ms |
384 KB |
Output is correct |
8 |
Correct |
5 ms |
384 KB |
Output is correct |
9 |
Correct |
6 ms |
384 KB |
Output is correct |
10 |
Correct |
7 ms |
512 KB |
Output is correct |
11 |
Correct |
15 ms |
768 KB |
Output is correct |
12 |
Correct |
21 ms |
1152 KB |
Output is correct |
13 |
Correct |
46 ms |
2688 KB |
Output is correct |
14 |
Correct |
65 ms |
3748 KB |
Output is correct |
15 |
Correct |
110 ms |
6272 KB |
Output is correct |
16 |
Correct |
126 ms |
6784 KB |
Output is correct |
17 |
Correct |
182 ms |
9856 KB |
Output is correct |
18 |
Correct |
195 ms |
11008 KB |
Output is correct |
19 |
Correct |
258 ms |
14584 KB |
Output is correct |
20 |
Correct |
303 ms |
16248 KB |
Output is correct |