Submission #210247

#	Time	Username	Problem	Language	Result	Execution time	Memory
210247		Geothermal	Bigger segments (IZhO19_segments)	C++14	0 / 100	5 ms	380 KiB

segments

#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")
 
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
 
using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
 
typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;
 
typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
 
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;
 
#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)
 
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
 
const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001; //check the limits, dummy
 
int main() {
	ios_base::sync_with_stdio(0); cin.tie(0);    
	
    int N; cin >> N;
    ll last = -1;
    ll cur = 0;
    int ans = 0;
    vl vals;
    F0R(i, N) {
        ll X; cin >> X; cur += X; vals.pb(X);
        if (cur >= last) {

            F0R(j, sz(vals)) {
                ll Y = vals[j];
                if (cur - Y >= last + Y) {
                    cur -= Y; last += Y;
                } else break;
            }
            vals.clear();

            last = cur; cur = 0; ans++;
        }
    }
    cout << ans << endl;
	
	return 0;
}
 
// read the question correctly (ll vs int)
// template by bqi343

• Subtask 1: 0 / 13
• Subtask 2: 0 / 14
• Subtask 3: 0 / 10
• Subtask 4: 0 / 36
• Subtask 5: 0 / 27