Submission #209169

#	Time	Username	Problem	Language	Result	Execution time	Memory
209169		Blerargh	Foehn Phenomena (JOI17_foehn_phenomena)	C++17	0 / 100	6 ms	504 KiB

foehn_phenomena

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef long double ld;
typedef pair<ll,ll> ii;
typedef pair<ld,ld> id;

#define FOR(i, a, b) for(int i=(a); i<=(b); i++)
#define ROF(i, a, b) for(int i=(a); i>=(b); i--)
#define MEM(x, v) memset(x, v, sizeof(x))
#define SORT(x) sort((x).begin(), (x).end())
#define CMPSORT(x, cp) sort((x).begin(), (x).end(), cp)
#define FAST ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);

#define f first
#define s second
#define ins insert
#define e emplace
#define eb emplace_back
#define ef emplace_front
#define p push
#define pf push_front
#define pb push_back
#define mp make_pair
#define ub upper_bound
#define lb lower_bound
#define ft front
#define bk back
#define pp pop
#define ppb pop_back
#define ppf pop_front

#define db cout<<"YEET\n";
#define ct(x) cout<<x<<'\n';

const ll MOD = 1e9+7; //998244353
const ll MX = 2e5+5;
const ll INF = 1e18;
const ld PI = acos((ld)-1);

int main(){
    ll n, q, s, t, x, temp=0;
    ll diff[100];
    cin >> n >> q >> s >> t >> x;
    FOR(i,1,n){
        ll prev = x;
        cin >> x;
        diff[i] = x-prev;
        if (diff[i]>=0) temp-=diff[i]*s;
        else temp+=-diff[i]*t;
    }

    ll a, b, c;
    FOR(i,1,q){
        cin >> a >> b >> c;
        ll olda = diff[a];
        ll newa = diff[a]+=c;
        if (olda<=0 && newa<=0) temp-=c*t;
        else if (olda>=0 && newa>=0) temp-=c*s;
        else if (olda>=0 && newa<=0) temp+=olda*s, temp-=newa*t;
        else if (olda<=0 && newa>=0) temp+=olda*t, temp-=newa*s;

        if (b==n) {
            cout << temp << '\n';
            continue;
        }
        else {
            ll oldb = diff[b+1];
            ll newb = diff[b+1]-=c;
            if (oldb<=0 && newb<=0) temp+=c*t;
            else if (oldb>=0 && newb>=0) temp+=c*s;
            else if (olda>=0 && newa<=0) temp-=oldb*s, temp+=newb*t;
            else if (olda<=0 && newa>=0) temp-=oldb*t, temp+=newb*s;
        }
        cout << temp << '\n';
    }
}

• Subtask 1: 0 / 30
• Subtask 2: 0 / 10
• Subtask 3: 0 / 60