| # | Time | Username | Problem | Language | Result | Execution time | Memory |
|---|---|---|---|---|---|---|---|
| 20842 | sgc109 | 초음속철도 (OJUZ11_rail) | C++11 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// #include <bits/stdc++.h>
#include <unordered_set>
// #include <unordered_map>
#include <vector>
#include <cstdio>
#include <iostream>
#include <cstring>
#include <queue>
#include <set>
#include <map>
#include <cmath>
#include <algorithm>
#include <utility>
#include <string>
#define REP(i,a,b) for(int i=a;i<=b;++i)
#define FOR(i,n) for(int i=0;i<n;++i)
#define pb push_back
#define all(v) (v).begin(),(v).end()
#define sz(v) ((int)(v).size())
#define inp1(a) scanf("%d",&a)
#define inp2(a,b) scanf("%d%d",&a,&b)
#define inp3(a,b,c) scanf("%d%d%d",&a,&b,&c)
#define inp4(a,b,c,d) scanf("%d%d%d%d",&a,&b,&c,&d)
#define inp5(a,b,c,d,e) scanf("%d%d%d%d%d",&a,&b,&c,&d,&e)z
using namespace std;
typedef long long ll;
typedef pair<ll,ll> pll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef pair<int,int> pii;
typedef vector<pii> vii;
typedef vector<pll> vll;
typedef vector<vector<int> > vvi;
typedef pair<int,pair<int,int> > piii;
typedef vector<piii> viii;
const double EPSILON = 1e-9;
const double PI = acos(-1);
const int MOD = 1000000007;
const int INF = 0x3c3c3c3c;
const long long INFL = 0x3c3c3c3c3c3c3c3c;
const int MAX_N = 102;
struct Range{
int l,r;
bool operator<(Range& rhs){
if(l==rhs.l) return r<rhs.r;
return l<rhs.l;
}
};
int N,M,a,b,E;
Range ranges[200003];
ll dp[3610003];
ll lz[3610003];
unordered_set<int> us;
ll query(int nl, int nr, int l, int r, int nd){
if(lz[nd]) (dp[nd]*=2)%=MOD,(nl!=nr?lz[2*nd]=1,lz[2*nd+1]=1:0),lz[nd]=0;
if(l<=nl&&nr<=r) return dp[nd];
if(r<nl||nr<l) return 0;
return (query(nl,(nl+nr)/2,l,r,2*nd)+query((nl+nr)/2+1,nr,l,r,2*nd+1))%MOD;
} ll query(int l, int r){return query(0,E,l,r,1);}
void update(int nl, int nr, int l, int r, int nd){
if(lz[nd]) (dp[nd]*=2)%=MOD,(l!=r?lz[2*nd]=1,lz[2*nd+1]=1:0),lz[nd]=0;
if(l<=nl&&nr<=r) {(dp[nd]*=2)%=MOD,(nl!=nr?lz[2*nd]=lz[2*nd+1]=1:0);return;}
if(r<nl||nr<l) return;
update(nl,(nl+nr)/2,l,r,2*nd),update((nl+nr)/2+1,nr,l,r,2*nd+1),dp[nd]=(dp[2*nd]+dp[2*nd+1])%MOD;
} void update(int l, int r){update(0,E,l,r,1);}
void pUpdate(int nl, int nr, int nd, int pos, int val){
if(lz[nd]) (dp[nd]*=2)%=MOD,(l!=r?lz[2*nd]=1,lz[2*nd+1]=1:0),lz[nd]=0;
if(nl==nr&&nl==pos) {dp[nd]=val;return;}
if(nr<pos||pos<nl) return;
pUpdate(nl,(nl+nr)/2,2*nd,pos,val),pUpdate((nl+nr)/2+1,nr,2*nd+1,pos,val),dp[nd]=(dp[2*nd]+dp[2*nd+1])%MOD;
} void pUpdate(int pos, int val){pUpdate(0,E,1,pos,val);}
int main() {
vi sorted;
inp2(N,M);
us.insert(1),sorted.pb(1);
us.insert(N),sorted.pb(N);
FOR(i,M){
inp2(a,b);
ranges[i]=Range{a,b};
if(!us.count(a)) us.insert(a),sorted.pb(a);
if(!us.count(b)) us.insert(b),sorted.pb(b);
}
sort(all(sorted));
E=sz(sorted)-1;
FOR(i,M) {
ranges[i].l=lower_bound(all(sorted),ranges[i].l)-sorted.begin();
ranges[i].r=lower_bound(all(sorted),ranges[i].r)-sorted.begin();
}
sort(ranges,ranges+M);
// 좌표압축 + 정렬까지 완료
pUpdate(0,1);
FOR(i,M){
pUpdate(ranges[i].r,query(ranges[i].l,ranges[i].r)+query(ranges[i].r,ranges[i].r));
update(ranges[i].r+1,E);
}
printf("%lld",query(E,E));
return 0;
}