Submission #208055

#	Time	Username	Problem	Language	Result	Execution time	Memory
208055		rzbt	Split the sequence (APIO14_sequence)	C++14	71 / 100	95 ms	131076 KiB

sequence

#include <bits/stdc++.h>
#define mp make_pair
#define pb push_back
#define F first
#define S second
#define all(x) x.begin(),x.end()
#define MAXN 100005
#define MAXK 205
typedef long long ll;


using namespace std;

ll n,u;
ll dp[MAXN][2];
ll niz[MAXN];
ll suma[MAXN];
ll sec[MAXN][MAXK];
pair<ll,ll> prava[MAXN];
vector<pair<pair<ll,ll>,ll> > prave;

int main()
{
    scanf("%lld %lld", &n, &u);

    for(ll i=1;i<=n;i++)
        scanf("%lld",niz+i);
    for(ll i=1;i<=n;i++)
        suma[i]=suma[i-1]+niz[i];


    for(ll k=1;k<=u;k++){
        prave.clear();
        for(int i=1;i<=n;i++)dp[i][0]=dp[i][1];
        for(ll d=k+1;d<=n;d++){
            pair<ll,ll> t=mp(suma[d-1],-suma[d-1]*suma[d-1]+dp[d-1][0]);
            prava[d-1]=t;
            while(!prave.empty()){
                pair<ll,ll> posl=prava[prave.back().S];
                if(posl.F==t.F){
                    prave.pop_back();
                    continue;
                }
                ll presek=(posl.S-t.S)/(t.F-posl.F)+((posl.S-t.S)%(posl.F-t.F)==0?0:1);
                if(presek>10000000000000000ll)exit(2);
                if(presek<=prave.back().F.F){
                    prave.pop_back();
                    continue;
                }
                prave.back().F.S=presek-1;
                prave.pb(mp(mp(presek,10000000000000000ll),d-1));
                break;
            }
            if(prave.empty()){
                prave.pb(mp(mp(0ll,10000000000000000ll),d-1));
            }
            ll l=0,r=prave.size()-1,sol=-1;
            while(l<=r){
                ll mid=(l+r)/2;
                if(prave[mid].F.F<=suma[d]){
                    sol=prave[mid].S;
                    l=mid+1;
                }else
                    r=mid-1;

            }
            dp[d][1]=prava[sol].F*suma[d]+prava[sol].S;
            sec[d][k]=sol;

            /**
            dp[d][k]=-1;
            for(ll i=k+1;i<=d;i++){
                ll tr=suma[i-1]*(suma[d]-suma[i-1])+dp[i-1][k-1];
                if(tr>dp[d][k]){
                    sec[d][k]=i-1;
                    dp[d][k]=tr;
                }

            }
            */
            //printf("   %lld %lld    %lld\n",d,k,dp[d][k]);
            /*for(auto x:prave){
                printf("     %lld %lld      %lld %lld\n",x.F.F,x.F.S,prava[x.S][k-1].F,prava[x.S][k-1].S);
            }
            printf("\n");*/
        }
    }

    printf("%lld\n",dp[n][1]);
    ll poc=n;
    for(ll i=u;i>0;i--){
        poc=sec[poc][i];
        printf("%lld ",poc);
    }
    return 0;
}

Compilation message (stderr)

sequence.cpp: In function 'int main()':
sequence.cpp:24:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%lld %lld", &n, &u);
     ~~~~~^~~~~~~~~~~~~~~~~~~~~
sequence.cpp:27:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%lld",niz+i);
         ~~~~~^~~~~~~~~~~~~~

• Subtask 1: 11 / 11
• Subtask 2: 11 / 11
• Subtask 3: 11 / 11
• Subtask 4: 17 / 17
• Subtask 5: 21 / 21
• Subtask 6: 0 / 29