Submission #207910

#	Time	Username	Problem	Language	Result	Execution time	Memory
207910		Blerargh	JJOOII 2 (JOI20_ho_t2)	C++17	1 / 100	5 ms	380 KiB

ho_t2

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef long double ld;
typedef pair<ll,ll> ii;
typedef pair<ld,ld> id;

#define FOR(i, a, b) for(int i=(a); i<=(b); i++)
#define ROF(i, a, b) for(int i=(a); i>=(b); i--)
#define MEM(x, v) memset(x, v, sizeof(x))
#define SORT(x) sort((x).begin(), (x).end())
#define CMPSORT(x, cp) sort((x).begin(), (x).end(), cp)
#define FAST ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define getchar_unlocked _getchar_nolock

#define f first
#define s second
#define ins insert
#define e emplace
#define eb emplace_back
#define ef emplace_front
#define p push
#define pf push_front
#define pb push_back
#define mp make_pair
#define ub upper_bound
#define lb lower_bound
#define ft front
#define bk back
#define pp pop
#define ppb pop_back
#define ppf pop_front

#define db cout<<"YEET\n";
#define ct(x) cout<<x<<'\n';

const ll MOD = 1e9+7; //998244353
const ll MX = 2e5+5;
const ll INF = 1e18;
const ld PI = acos((ld)-1);

int main(){ 
    FAST
    ll n, k;
    string ss = "";
    deque<ll> idj, ido, idi, idj1;
    cin >> n >> k;
    FOR(i, 1, n){
        char c;
        cin >> c;
        ss+=c;
        if (c == 'J') idj.pb(i);
        if (c == 'I') idi.pb(i);
    }

    ll op = INF;
    FOR(i, 1, n){
        if ((ido.empty() || (ll)idj.ft() < (ll)ido.ft()) && !idj.empty() && idj.ft() < i) idj1.pb(idj.ft()), idj.ppf(); 
        while ((ll)idj1.size()>k) idj1.ppf();

        while (!idi.empty() && i > (ll)idi.ft()) idi.ppf();

        if (ss[i-1] == 'O'){
            ido.pb(i);
            if ((ll)ido.size()==k){
                ido.ppf();
                if ((ll)idj1.size()>=k && (ll)idi.size()>=k) {
                    ll ops = idi[k-1] - idj1.ft()+1;
                    ops -= k*3;
                    op = min(op, ops);
                }
            }
        }
    }
    if (op == INF) cout << "-1";
    else cout << op;
}

• Subtask 1: 1 / 1
• Subtask 2: 0 / 12
• Subtask 3: 0 / 87