Submission #207755

#TimeUsernameProblemLanguageResultExecution timeMemory
207755mode149256Commuter Pass (JOI18_commuter_pass)C++14
100 / 100
566 ms19572 KiB
/*input 10 15 6 8 7 9 2 7 12 8 10 17 1 3 1 3 8 14 5 7 15 2 3 7 1 10 14 3 6 12 1 5 10 8 9 1 2 9 7 1 4 1 1 8 1 2 4 7 5 6 16 */ #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll, ll> pl; typedef pair<ld, ld> pd; typedef vector<int> vi; typedef vector<vi> vii; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<vl> vll; typedef vector<pi> vpi; typedef vector<vpi> vpii; typedef vector<pl> vpl; typedef vector<cd> vcd; typedef vector<pd> vpd; typedef vector<bool> vb; typedef vector<vb> vbb; typedef std::string str; typedef std::vector<str> vs; #define x first #define y second #define debug(...) cout<<"["<<#__VA_ARGS__<<": "<<__VA_ARGS__<<"]\n" const int MOD = 1000000007; const ll INF = (ll)1e15; const int MX = 100101; const ld PI = 3.14159265358979323846264338327950288419716939937510582097494L; template<typename T> pair<T, T> operator+(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x + b.x, a.y + b.y); } template<typename T> pair<T, T> operator-(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x - b.x, a.y - b.y); } template<typename T> T operator*(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.x + a.y * b.y); } template<typename T> T operator^(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.y - a.y * b.x); } template<typename T> void print(vector<T> vec, string name = "") { cout << name; for (auto u : vec) cout << u << ' '; cout << '\n'; } int N, M, S, T, U, V; vpi edges[MX]; ll minDist; void find(int start, vl &dist) { dist = vl(N, INF); dist[start] = 0; priority_queue<pl, vpl, greater<pl>> pq; pq.push({0, start}); while (pq.size()) { pl curr = pq.top(); pq.pop(); int c = (int)curr.y; ll d = curr.x; if (d > dist[c]) continue; for (auto u : edges[c]) { if (dist[u.x] > d + u.y) { dist[u.x] = d + u.y; pq.push({dist[u.x], u.x}); } } } } // dp[i] = min(fromU[j]) f.a. j on shortest path T-S to i void doDP(int st, vl &dp, const vl &fromU, const vl &fromPir, const vl &fromKitas) { dp = vl(N, INF); dp[st] = fromU[st]; priority_queue<pl, vpl, greater<pl>> pq; pq.push({dp[st], st}); while (pq.size()) { pl curr = pq.top(); pq.pop(); int c = (int)curr.y; ll d = curr.x; if (d > dp[c]) continue; for (auto u : edges[c]) { // printf("d = %lld, u = %d %d, dist = %lld\n", d, u.x, u.y, d + u.y + fromKitas[u.x]); if (fromPir[c] + u.y + fromKitas[u.x] == minDist and min(dp[c], fromU[u.x]) < dp[u.x]) { dp[u.x] = min(dp[c], fromU[u.x]); pq.push({dp[u.x], u.x}); } } } } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> N >> M >> S >> T >> U >> V; S--; T--; U--; V--; for (int i = 0; i < M; ++i) { int a, b, w; cin >> a >> b >> w; a--; b--; edges[a].emplace_back(b, w); edges[b].emplace_back(a, w); } vl fromU, fromV; vl fromT, fromS; find(U, fromU); find(V, fromV); find(T, fromT); find(S, fromS); minDist = fromS[T]; // void doDP(int st, vl & dp, const vl & fromU, const vl & fromS) { vl dpT, dpS; doDP(T, dpT, fromU, fromT, fromS); doDP(S, dpS, fromU, fromS, fromT); // print(dpT); // print(dpS); vl dist(N, INF); dist[T] = 0; priority_queue<pl, vpl, greater<pl>> pq; pq.push({0, T}); ll ats = fromU[V]; while (pq.size()) { pl curr = pq.top(); pq.pop(); int c = (int)curr.y; ll d = curr.x; // printf("c = %d, fromV = %lld, dpt = %lld, dps = %lld, ats = %lld\n", c, // fromV[c], dpT[c], dpS[c], ats); ats = min(ats, fromV[c] + min(dpT[c], dpS[c])); if (d > dist[c]) continue; for (auto u : edges[c]) { if (d + u.y + fromS[u.x] == minDist and dist[u.x] == INF) { dist[u.x] = d + u.y; pq.push({dist[u.x], u.x}); } } } printf("%lld\n", ats); } /* Look for: * special cases (n=1?) * overflow (ll vs int?) * the exact constraints (multiple sets are too slow for n=10^6 :( ) * array bounds */
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