Submission #205064

#TimeUsernameProblemLanguageResultExecution timeMemory
205064mode149256Pipes (BOI13_pipes)C++14
100 / 100
316 ms42232 KiB
/*input 3 3 9 4 6 1 2 2 3 3 1 7 7 2 2 2 2 2 2 2 1 2 2 3 3 4 4 5 5 6 6 7 7 1 */ #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll, ll> pl; typedef pair<ld, ld> pd; typedef vector<int> vi; typedef vector<vi> vii; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<vl> vll; typedef vector<pi> vpi; typedef vector<vpi> vpii; typedef vector<pl> vpl; typedef vector<cd> vcd; typedef vector<pd> vpd; typedef vector<bool> vb; typedef vector<vb> vbb; typedef std::string str; typedef std::vector<str> vs; #define x first #define y second #define debug(...) cout<<"["<<#__VA_ARGS__<<": "<<__VA_ARGS__<<"]\n" const int MOD = 1000000007; const ll INF = std::numeric_limits<ll>::max(); const int MX = 500101; const ld PI = 3.14159265358979323846264338327950288419716939937510582097494L; template<typename T> pair<T, T> operator+(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x + b.x, a.y + b.y); } template<typename T> pair<T, T> operator-(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x - b.x, a.y - b.y); } template<typename T> T operator*(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.x + a.y * b.y); } template<typename T> T operator^(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.y - a.y * b.x); } template<typename T> void print(vector<T> vec, string name = "") { cout << name; for (auto u : vec) cout << u << ' '; cout << '\n'; } vl W(MX); int N, M; vector<vpi> edges(MX); vi sz(MX, 0); vb done(MX, false); vl ats(MX, -1); void bad() { printf("0\n"); exit(0); } vb visited(MX, false); int cnt = 0; void dfs(int v) { cnt++; visited[v] = true; for (auto u : edges[v]) if (!visited[u.x] and !done[u.y]) dfs(u.x); } vi nodes; vi edg; int prad; void dfs2(int v, int p) { if (visited[v]) return; nodes.push_back(v); visited[v] = true; for (auto u : edges[v]) { if (!done[u.y] and u.x != p) { edg.push_back(u.y); dfs2(u.x, v); break; } } } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> N >> M; for (int i = 0; i < N; ++i) cin >> W[i]; for (int i = 0; i < M; ++i) { int a, b; cin >> a >> b; a--; b--; sz[a]++; sz[b]++; edges[a].push_back({b, i}); edges[b].push_back({a, i}); } queue<int> vienas; for (int i = 0; i < N; ++i) { if (sz[i] == 1) vienas.push(i); } while (vienas.size()) { int c = vienas.front(); vienas.pop(); for (auto u : edges[c]) { if (done[u.y]) continue; sz[c]--; sz[u.x]--; done[u.y] = true; ats[u.y] = 2 * W[c]; W[u.x] -= W[c]; if (sz[u.x] == 1) vienas.push(u.x); break; } } bool visi2 = true; for (int i = 0; i < N; ++i) { if (sz[i] != 2 and sz[i] != 0) { visi2 = false; break; } } if (!visi2) bad(); for (int i = 0; i < N; ++i) { if (visited[i]) continue; cnt = 0; dfs(i); if (cnt % 2 == 0) bad(); } visited = vb(MX, false); auto daryk = [&]() { int K = (int)nodes.size(); ll visux = 0; for (int i = 0; i < K; ++i) visux += W[nodes[i]]; // printf("visux = %lld\n", visux); ll curr = 0; for (int i = 0; i < K; i += 2) curr += 2 * W[nodes[i]]; for (int i = 0; i < K; i += 2) { curr -= 2 * W[nodes[i]]; ats[edg[i]] = visux - curr; if (i + 1 < K) curr += 2 * W[nodes[i + 1]]; } curr = 0; for (int i = 1; i < K; i += 2) curr += 2 * W[nodes[i]]; for (int i = 1; i < K; i += 2) { curr += 2 * W[nodes[i - 1]]; curr -= 2 * W[nodes[i]]; ats[edg[i]] = visux - curr; } }; for (int i = 0; i < N; ++i) { if (!visited[i]) { nodes.clear(); edg.clear(); dfs2(i, -1); if ((int)nodes.size() == 1) continue; // print(nodes); daryk(); } } for (int i = 0; i < M; ++i) printf("%lld\n", ats[i]); } /* Look for: * special cases (n=1?) * overflow (ll vs int?) * the exact constraints (multiple sets are too slow for n=10^6 :( ) * array bounds */
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