# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|
20106 | | kk1401 | 괄호 (kriii4_R) | C++98 | | 390 ms | 32332 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<stdio.h>
#define M 1000001
#define T 1000000007
long long power[M],k,fact[M],d[M],f[M];
int n;
long long Pow(long long a)
{
long long i,t=1ll,ans=1ll;
int c=0;
f[0] = a;
for(i=1; ; i++){
f[i] = (f[i-1] * f[i-1]) % T;
t*=2ll;
if(t>=T) break;
}
for(t = T-2;;){
if(t&1) ans = (ans * f[c]) % T;
c++; t/=2ll;
if(t==0) break;
}
return ans;
}
long long catalan(int a)
{
return (((Pow(a+1)*Pow(fact[a]))%T) * ((Pow(fact[a])*fact[2*a])%T))%T;
}
int main()
{
int i;
scanf("%d%lld",&n,&k);
power[0] = fact[0] = 1ll;
for(i=1; i<=n; i++) power[i] = (power[i-1] * k) % T;
for(i=1; i<=2*n; i++) fact[i] = (fact[i-1] * i) % T;
d[1] = k;
for(i=2; i<=n; i++){
if(i%2 == 0) d[i] = (d[i-1] * (k + 1ll)) % T;
else d[i] = ((d[i-1] * (k+1)) % T - (power[(i-1)/2] * catalan((i-1)/2)) % T + T) % T;
}
printf("%lld",d[n]);
return 0;
}
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