Submission #200814

#	Time	Username	Problem	Language	Result	Execution time	Memory
200814		balbit	Soccer (JOI17_soccer)	C++14	35 / 100	40 ms	2548 KiB

soccer

#include <bits/stdc++.h>
using namespace std;

#define ll long long

#define int ll
#define pii pair<int, int>
#define ull unsigned ll
#define f first
#define s second
#define FOR(i,a,b) for (int i=(a); i<(b); ++i)
#define REP(i,n) FOR(i,0,n)
#define RREP(i,n) for (int i=(n-1); i>=0; --i)
#define REP1(i,n) FOR(i,1,n+1)
#define ALL(x) x.begin(),x.end()
#define SZ(x) (int)x.size()
#define SQ(x) (x)*(x)
#define MN(a,b) a = min(a,(__typeof__(a))(b))
#define MX(a,b) a = max(a,(__typeof__(a))(b))
#define pb push_back
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
#ifdef BALBIT
#define IOS()
#define bug(...) fprintf(stderr,"#%d (%s) = ",__LINE__,#__VA_ARGS__),_do(__VA_ARGS__);
template<typename T> void _do(T &&x){cerr<<x<<endl;}
template<typename T, typename ...S> void _do(T &&x, S &&...y){cerr<<x<<", ";_do(y...);}
#else
#define IOS() ios_base::sync_with_stdio(0);cin.tie(0);
#define endl '\n'
#define bug(...)
#endif

const int iinf = 1<<29;
const ll inf = 1ll<<60;
const ll mod = 1e9+7;


void GG(){cout<<"-1\n"; exit(0);}

ll mpow(ll a, ll n, ll mo = mod){ // a^n % mod
    ll re=1;
    while (n>0){
        if (n&1) re = re*a %mo;
        a = a*a %mo;
        n>>=1;
    }
    return re;
}

ll inv (ll b){
    return b==1?1:(mod-mod/b) * inv(mod%b) % mod;
}

const int maxn = 1005;

int n, m;
ll A,B,C;
ll d[maxn];
int r[maxn],c[maxn];

signed main(){
    IOS();
    cin>>n>>m;
    cin>>A>>B>>C;
    int N; cin>>N;
    REP(i,N){
        cin>>r[i]>>c[i];
    }
    priority_queue<pii, vector<pii>, greater<pii> > pq;
    pq.push({0,0});
    fill(d, d+maxn, inf);
    d[0]=0;
    while (!pq.empty()){
        int v = pq.top().s; ll w = pq.top().f;pq.pop();
        if (d[v]!=w) continue;
        REP(i,N){
            if (i!=v){
                ll dto = 0;
                ll d1 = abs(r[i]-r[v]), d2 = abs(c[i]-c[v]);
                dto = min({C*d1+C*d2,C*d1+ B+A*d2,B+A*d1 +C*d2});
                if (d[i]>d[v]+dto){
                    d[i]=d[v]+dto;
                    pq.push({d[i],i});
                }
            }
        }
    }
//    bug(d[1]);
    cout<<d[N-1]<<endl;
    // Check your array bounds!
    // Think about corner cases (smallest or biggest?)
}

• Subtask 1: 5 / 5
• Subtask 2: 30 / 30
• Subtask 3: 0 / 65