Submission #19923

#TimeUsernameProblemLanguageResultExecution timeMemory
19923myungwoo팔찌 (kriii4_V)C++14
0 / 100
0 ms32364 KiB
#include<stdio.h> #include<memory.h> #define mod 1000000007 #define inv(a) exp(a,mod-2) typedef long long lld; lld exp(lld a, lld b){ if(b==0)return 1; lld k=exp(a, b/2); k=(k*k)%mod; if(b%2)k=(k*a)%mod; return k; } lld fac[1001001], rfac[1001001]; void init(){ lld i; fac[0]=rfac[0]=1; for(i=1; i<=1000000; i++){ fac[i]=(fac[i-1]*i)%mod; rfac[i]=inv(fac[i]); } } lld comb(lld a, lld b){ return fac[a]*rfac[b]%mod*rfac[a-b]%mod; } lld n, k; lld all[1001001]; lld all2[1001001]; lld sum, lr, dap; int main(){ lld i, j; // init(); scanf("%lld%lld", &n, &k); all[0]=1; for(i=1; i<=n; i++){ all[i]%=mod; if(all[i]<0)all[i]+=mod; all[i]+=exp(k,i), all[i]%=mod; for(j=2*i; j<=n; j+=i)all[j]-=all[i]; } for(i=1; i<=n; i++){ sum += all[i]*(n/i)%mod * inv(i); sum %= mod; } all2[0]=1; for(i=1; i<=n; i++){ all2[i]%=mod; if(all2[i]<0)all2[i]+=mod; all2[i]+=exp(k,i/2+1), all2[i]%=mod; for(j=2*i; j<=n; j+=i)all2[j]-=all2[i]; } all2[4]=2; for(i=1; i<=n; i++){ lld im = all2[i]*(n/i)%mod; if(i%2 == 0)im *= inv(2); // else im *= inv(i); lr += im; lr %= mod; } // if(n>=2)lr += all[2]*inv(2), lr%=mod; dap = (sum+lr)*inv(2)%mod; dap = (dap+1)%mod; printf("%lld", dap); return 0; }
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