Submission #197512

#	Time	Username	Problem	Language	Result	Execution time	Memory
197512		GSmerch	Maxcomp (info1cup18_maxcomp)	C++14	0 / 100	26 ms	9976 KiB

maxcomp

#include <bits/stdc++.h>

typedef long long ll;
typedef long double ld;


using namespace std;

#define fi first
#define se second
#define sz(x) (x).size()
#define pll pair<ll,ll >
#define pb push_back
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define endln '\n'
#define cont continue

const ll MaxN = 1e3 + 100;
const ll LogN = 20;
ll Inf = 1e18;
const ll dx[4] = { 0,1,0,-1 };
const ll dy[4] = { 1,0,-1,0 };

bool used[MaxN][MaxN];
ll Mt[MaxN][MaxN];
ll dp[MaxN][MaxN];

struct el{
    ll c, x, y;
};
int main() {

#ifdef LOCAL
    ifstream cin("input.txt");
    ofstream cout("output.txt");
#else
    //ifstream cin("points.in");
    //ofstream cout("points.out");
#endif
    ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);

    ll N, M;
    cin>>N>>M;
    vector<el > St;
    for(int i = 1;i<=N;i++){
        for(int j =1;j<=M;j++){
            cin>>Mt[i][j];
            used[i][j] = 1;
            St.pb({Mt[i][j], i, j});
        }
    }
    sort(all(St),[=](el a, el b){
         return a.c < b.c;
    });

    ll Ans = -Inf;
    memset(dp, -1, sizeof(dp));
    for(el a : St){
        cerr<<a.c <<' ' <<a.x <<' '<<a.y<<endln;
        ll k = -1;
        for(int i =0;i<4;i++){
            if(used[a.x + dx[i]][a.y + dy[i]]){
                if(Mt[a.x + dx[i]][a.y + dy[i]] < a.c){
                    k = max(k,a.c + dp[a.x + dx[i]][a.y + dy[i]] - Mt[a.x + dx[i]][a.y + dy[i]] - 1 );
                }
            }
        }
        dp[a.x][a.y] = k;
        for(int i =0;i<4;i++){
            if(used[a.x + dx[i]][a.y + dy[i]]){
                if(Mt[a.x + dx[i]][a.y + dy[i]] <= a.c){
                    dp[a.x][a.y] = max(dp[a.x][a.y], dp[a.x + dx[i]][a.y + dy[i]] - 1);
                    dp[a.x + dx[i]][a.y + dy[i]] = max(dp[a.x][a.y] - 1, dp[a.x + dx[i]][a.y + dy[i]]);
                    //k = max(k,dp[a.x + dx[i]][a.y + dy[i]] - Mt[a.x + dx[i]][a.y + dy[i]] - 1 );
                }
            }
        }
        //dp[a.x][a.y] = max(dp[a.x + dx[i]][a.y + dy[i]], dp[a.x][a.y]);
        Ans = max(dp[a.x][a.y], Ans);
    }
    cout<<Ans;

    return 0;
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 15
• Subtask 3: 0 / 30
• Subtask 4: 0 / 40