Submission #197209

#TimeUsernameProblemLanguageResultExecution timeMemory
197209PankinXOR Sum (info1cup17_xorsum)C++14
45 / 100
1613 ms15024 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #pragma GCC optimize("unroll-loops") #pragma GCC optimize("Ofast") #pragma GCC optimize("-O3") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #define mp make_pair #define ll long long #define ld long double #define pb push_back #define fast_io ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define fs first #define sc second #define getfiles ifstream cin("input.txt"); ofstream cout("output.txt"); #define endl '\n' #define pii pair<int, int> const int INF = 2000000005; const ll BIG_INF = 2000000000000000005; const int mod = 1000000007; const int P = 31; const ld PI = 3.141592653589793238462643; const double eps = 1e-9; using namespace std; using namespace __gnu_pbds; bool valid(int x, int y, int n, int m) { return x >= 0 && y >= 0 && x < n && y < m; } mt19937 rng(1999999973); typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ordered_set; const int N = 1000000 + 5; int order[N], p[2][N], o[2], a[N], n, ans = 0; inline int readint() { int x = 0; char ch = getchar_unlocked(); while (ch < '0' || ch > '9') { ch = getchar_unlocked(); } while (ch >= '0' && ch <= '9') { x = (x << 3) + (x << 1) + ch - '0'; ch = getchar_unlocked(); } return x; } signed main() { fast_io; n = readint(); for (int i = 0; i < n; i++) { a[i] = readint(); order[i] = i; } int curmask = 0; int pointer[2] = {o[0], o[1]}, same = 0, col = 0; for (int bit = 0; bit < 29; bit++) { o[0] = o[1] = 0; for (int i = 0; i < n; i++) { int v = (a[order[i]]>>bit)&1; p[v][o[v]] = order[i]; o[v]++; } pointer[0] = o[0], pointer[1] = o[1], same = 0, col = 0; for (int i = 0; i < n; i++) { for (int bt = 0; bt < 2; bt++) { while(pointer[bt] > 0 && (a[p[bt][pointer[bt] - 1]]&curmask) + (a[order[i]]&curmask) >= (1 << bit)) pointer[bt]--; if (((a[order[i]]>>bit)&1) != bt) col += pointer[bt]; else col += o[bt] - pointer[bt]; } if (((a[order[i]] + a[order[i]])>>bit)&1) same++; col &= 3; } col += 4 - (same&3); col >>= 1; col += same; ans |= ((col&1) << bit); int cur = 0; for (int bt = 0; bt < 2; bt++) { for (int i = 0; i < o[bt]; i++) { order[cur] = p[bt][i]; cur++; } } curmask <<= 1; curmask++; } cout << ans; return 0; } /* 2 7 0 */
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