# | Submission time | Handle | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
197013 | 2020-01-18T06:20:12 Z | dennisstar | None (KOI16_dist) | C++11 | 73 ms | 2312 KB |
#include <bits/stdc++.h> #define fi first #define se second #define ryan bear #define eb emplace_back #define all(V) (V).begin(), (V).end() #define unq(V) (V).erase(unique(all(V)), (V).end()) #define fastio ios::sync_with_stdio(false); cin.tie(0) using namespace std; typedef long long ll; typedef vector<ll> vlm; typedef vector<int> vim; typedef pair<ll, ll> pll; typedef pair<int, int> pii; int N, T; ll x[30010], y[30010], dx[30010], dy[30010]; pll operator -(pll p1, pll p2) { return pll(p1.fi-p2.fi, p1.se-p2.se); } int ccw(pll v1, pll v2) { if (v1.fi*v2.se-v1.se*v2.fi > 0) return 1; //ccw else if (v1.fi*v2.se-v1.se*v2.fi < 0) return -1; //cw else return 0; //collinear } int ccw1(pll p1, pll p2, pll p3) { return ccw(p2-p1, p3-p1); } int ccw2(pll p1, pll p2, pll p3, pll p4) { return ccw(p2-p1, p4-p3); } ll sq(int k) { return k*k; } vector<pll> make_ch(vector<pll> &P) { //convex hull sort(all(P)); unq(P); vector<pll> ch; for (auto &i:P) { while (ch.size()>1 && ccw1(ch[ch.size()-2], ch.back(), i)!=1) ch.pop_back(); ch.eb(i); } reverse(all(P)); int tp=ch.size(); for (auto &i:P) { while (tp<ch.size() && ccw1(ch[ch.size()-2], ch.back(), i)!=1) ch.pop_back(); ch.eb(i); } ch.pop_back(); return ch; } ll dist(vector<pll> &P) { P=make_ch(P); ll ret=0; for (int i=0, j=1; i<P.size(); i++) { while (ccw2(P[i], P[(i+1)%P.size()], P[j], P[(j+1)%P.size()])==1) j=(j+1)%P.size(); ret=max(ret, sq(P[i].fi-P[j].fi)+sq(P[i].se-P[j].se)); } return ret; } ll solve(int t) { vector<pll> P; for (int i=1; i<=N; i++) P.eb(x[i]+dx[i]*t, y[i]+dy[i]*t); return dist(P); } int main() { scanf("%d %d", &N, &T); for (int i=1; i<=N; i++) scanf("%lld %lld %lld %lld", &x[i], &y[i], &dx[i], &dy[i]); vector<pll> p; int s=0, e=T, mi=0; while (s<e-3) { int m1=(s*2+e)/3, m2=(s+e*2)/3; ll r1=solve(m1), r2=solve(m2); if (r1>r2) s=m1; else e=m2; } pll ans=pll((1ll<<60), (1ll<<60)); for (int i=s; i<=e; i++) ans=min(ans, pll(solve(i), (ll)i)); printf("%lld\n%lld\n", ans.se, ans.fi); return 0; }
Compilation message
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Incorrect | 2 ms | 376 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Incorrect | 2 ms | 376 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Incorrect | 73 ms | 2312 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Incorrect | 2 ms | 376 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |