# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
19406 | imsifile | Ω (kriii4_P3) | C++98 | 0 ms | 1084 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<stdio.h>
#define mod 1000000007
typedef long long lld;
lld a, b, sum;
lld exp(lld a, lld b){
if(b==0)return 1;
lld k=exp(a, b/2);
k=(k*k)%mod;
if(b%2)k=(k*a)%mod;
return k;
}
int n, k;
lld p, q, pq, mpq, dy[111], re;
double pr, d2[111];
int main(){
int n, i;
scanf("%lld%lld%d%d", &p, &q, &n, &k);
if(k==0 || p==q){puts("0"); return 0;}
if(k==n || q==0){puts("1"); return 0;}
pr = (double)q/p;
pq = q*exp(p,mod-2)%mod, mpq = (mod-pq)%mod;
dy[1]=1;
for(i=1; i<n; i++)dy[i+1] = (dy[i] + mpq*dy[i-1]%mod)*exp(1+mpq, mod-2)%mod;
d2[1]=1;
for(i=1; i<n; i++)d2[i+1] = (d2[i] - pr*d2[i-1])/(1-pr);
// for(i=0; i<=n; i++)printf("%lf ", d2[i]/d2[n]);
// puts("");
printf("%lld", dy[k]*exp(dy[n],mod-2)%mod);
return 0;
}
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