Submission #19255

#TimeUsernameProblemLanguageResultExecution timeMemory
19255kaTkaHr순열 (kriii4_T)C++14
8 / 100
2000 ms1084 KiB
#include <stdio.h> #include<vector> #include <algorithm> #include <map> using namespace std; typedef long long ll; const int MX = 105, MM = 1000000007; ll rv(ll A){ ll R = 1, B = MM-2; while(B){ if( B&1 ) R = R * A % MM; A = A * A % MM; B /= 2; } return R; } struct frac{ ll A, B; frac(ll A):A(A), B(1){} frac(ll a, ll b){ A = (a%MM+MM) % MM; B = (b%MM+MM) % MM; } frac(){A = 0, B = 1;} frac operator+ (const frac &l)const{ return frac((A * l.B + B * l.A) % MM, B * l.B % MM); } frac operator*(const frac &l)const{ return frac(A*l.A % MM, B*l.B % MM); } frac operator/(const frac &l)const{ return frac(A*l.B % MM, B*l.A % MM); } frac operator- (const frac &l)const{ return frac((A*l.B - B*l.A%MM + MM) % MM, B*l.B % MM); } ll v(){ return A * rv(B) % MM; } }; int main() { int N, KK; scanf("%d%d", &N, &KK); frac tot = 0; for(int K = KK+1; K <= N; K++){ frac ans = 0, mul = 1; for(int i = 1; i <= N; i++){ mul = mul * i; } for(int i = N; i >= 1; i--){ mul = mul / i; ans = ans + mul * (N-i+1); mul = mul * (i-K); } ans = ans * K * (N-K+1); tot = ans + tot; } printf("%lld\n", tot.v()); }
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