답안 #19014

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
19014 2016-02-17T04:14:45 Z tncks0121 카드 (kriii4_Z) C++14
0 / 100
0 ms 3292 KB
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <memory.h>
#include <math.h>
#include <assert.h>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <algorithm>
#include <string>
#include <functional>
#include <vector>
#include <deque>
#include <utility>
#include <bitset>
#include <limits.h>
#include <time.h>
#include <functional>
#include <numeric>
#include <iostream>
#include <unordered_map>
 
using namespace std;
typedef long long ll;
typedef unsigned long long llu;
typedef double lf;
typedef unsigned int uint;
typedef long double llf;
typedef pair<int, int> pii;
typedef pair<ll, int> pli;
 
#define debug(format, ...) printf(format, __VA_ARGS__);
 
const ll MOD = (ll)1e9 + 7;
 
ll modpow (ll a, ll b) {
    a %= MOD;
    ll ret = 1;
    while(b > 0) {
        if(b & 1) ret = (ret * a) % MOD;
        a = (a * a) % MOD;
        b >>= 1;
    }
    return ret;
}
 
struct mint {
    ll val;
    mint(ll val = 0): val((val % MOD + MOD) % MOD) { }
    mint operator+(mint p) { return val + p.val; }
    mint operator-(mint p) { return val - p.val; }
    mint operator*(mint p) { return val * p.val; }
    mint operator/(mint p) { return val * modpow(p.val, MOD-2); }
};


int N, L;
 
const int N_ = 3050, L_ = 3050;
 
int D[N_];
int freq[N_];
 
mint invfac[L_], inv[L_], fac[L_];

#define FO(i,a,b) for (int i = (a); i < (b); i++)
#define sz(v) int(v.size())

using namespace std;

typedef long double rl;
namespace FFT {
    struct cpl { rl a, b; cpl(rl a_=0, rl b_=0) : a(a_), b(b_) {}};
    cpl mul(cpl x, cpl y) { return {x.a*y.a-x.b*y.b,x.a*y.b+x.b*y.a}; }
    cpl add(cpl x, cpl y) { return {x.a+y.a,x.b+y.b}; }
    cpl sub(cpl x, cpl y) { return {x.a-y.a,x.b-y.b}; }

    const static int N = 1<<13;
    const static rl PI = acos(rl(-1));
    cpl wpw[N];

    void fft(vector<cpl> &a, bool inv) {
        int n = sz(a);
        assert(1 <= n && n <= N);
        assert((n & (n-1)) == 0);
        for (int i = 1, j = 0, b; i < n; i++) {
            for (b = n>>1; j >= b; b >>= 1) j -= b;
            j += b;
            if (i < j) swap(a[i],a[j]);
        }
        for (int b = 2; b <= n; b <<= 1) {
            rl ang = 2 * PI / b * (inv ? -1 : 1);
            cpl w = {cos(ang),sin(ang)};
            wpw[0] = {1,0};
            FO(i,1,b/2) wpw[i] = mul(w,wpw[i-1]);
            for (int i = 0; i < n; i += b) FO(j,0,b/2) {
                cpl u = a[i+j], v = mul(wpw[j], a[i+j+b/2]);
                a[i+j] = add(u,v);
                a[i+j+b/2] = sub(u,v);
            }
        }
        if (inv) FO(i,0,n) a[i].a /= n, a[i].b /= n;
    }

    vector<rl> rmul(const vector<rl> &a, const vector<rl> &b) {
        int n = 1;
        while (n < sz(a)+sz(b)) n <<= 1;
        n <<= 1;
        vector<cpl> A(n), B(n);
        FO(i,0,sz(a)) A[i] = {a[i],0};
        FO(i,0,sz(b)) B[i] = {b[i],0};
        fft(A,false); fft(B,false);
        FO(i,0,n) A[i] = mul(A[i],B[i]);
        fft(A,true);
        vector<rl> c(n);
        FO(i,0,n) c[i] = A[i].a;
        return c;
    }

    vector<long long> imul(const vector<int> &a, const vector<int> &b) {
        vector<rl> A(a.begin(),a.end()), B(b.begin(),b.end());
        vector<rl> C = rmul(A,B);
        vector<long long> c(sz(C));
        FO(i,0,sz(c)) c[i] = roundl(C[i]);
        return c;
    }

    vector<int> imulmod(const vector<int> &a, const vector<int> &b, int mod=MOD) {
        int B = (int)sqrt(mod);
        int n = sz(a), m = sz(b);
        vector<int> a0(n), a1(n), b0(m), b1(m);
        FO(i,0,n) { a0[i] = a[i]%B; a1[i] = a[i]/B; }
        FO(i,0,m) { b0[i] = b[i]%B; b1[i] = b[i]/B; }

        vector<long long> z0 = imul(a0,b0), z1 = imul(a0,b1), Z1 = imul(a1,b0), z2 = imul(a1,b1);
        FO(i,0,sz(z0)) {
            z0[i] += (z1[i]+Z1[i])%mod * B;
            z0[i] += z2[i]%mod * B * B;
            z0[i] %= mod;
        }
        vector<int> r(sz(z0));
        FO(i,0,sz(r)) r[i] = z0[i];

        return r;
    }
};


int main() {
    assert(scanf("%d%d", &N, &L) == 2);
    assert(1 <= N && N <= 3000);
    assert(1 <= L && L <= 3000);
    for(int i = 1; i <= N; i++) {
        assert(scanf("%d", D+i) == 1);
        assert(0 <= D[i] && D[i] <= 10);
        ++freq[D[i]];
    }
 
 	// precalc section
 	{
	    inv[1] = 1;
	    for(int i = 2; i < L_; i++) {
	        inv[i] = inv[MOD % i] * -(MOD / i);
	    }
	 
	    invfac[0] = fac[0] = 1;
	    for(int i = 1; i <= L; i++) {
	        fac[i] = fac[i-1] * i;
	        invfac[i] = invfac[i-1] * inv[i];
	    }
 	}
 
    vector<mint> tb(L+1, 0);
    tb[0] = 1;

    for(int d = 0; d <= 10; d++) if(freq[d] > 0) {
        vector<mint> base(L+1, 0);
        for(int j = d; j <= L; j++) base[j] = invfac[j];
 
        auto multiply = [](vector<mint> &p, vector<mint> &q) {
        	vector<int> a(p.size()), b(q.size());
		    for(int i = 0; i <= L; i++) a[i] = (p[i]).val;
		    for(int i = 0; i <= L; i++) b[i] = (q[i]).val;
		    vector<int> r = FFT::imulmod(a,b); r.resize(L+1);
		    vector<mint> ret(L+1);
		    for(int i = 0; i <= L; i++) ret[i] = r[i];
		    return ret;
        };
 
        vector<mint> coef, cur(L+1, 0);
        for(int j = d; j <= L; j++) cur[j] = invfac[j];
 
        for(int k = 0; (1<<k) <= freq[d]; k++) {
            if((freq[d] >> k) & 1) {
                if(coef.empty()) coef = cur;
                else coef = multiply(coef, cur);
            }
            cur = multiply(cur, cur);
        }
 
 		tb = multiply(coef, tb);
    }
 
    mint ans = tb[L] * fac[L] / modpow(N, L);
    printf("%lld\n", ans.val);
 
    return 0;
}
# 결과 실행 시간 메모리 Grader output
1 Runtime error 0 ms 3292 KB gettid (syscall #186) was called by the program (disallowed syscall)
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Halted 0 ms 0 KB -