Submission #182110

#TimeUsernameProblemLanguageResultExecution timeMemory
182110lobo_prixSplit the sequence (APIO14_sequence)C++17
89 / 100
1787 ms91308 KiB
#include <bits/stdc++.h> using namespace std;using f64 = double;using i64=long long;using u64=unsigned long long; template<typename T> using Arr=vector<T>; #define hfor(v, s, e) for(int v=(s);(s)<=v&&v<(e);++v)//half-opened range #define hfori(v, s, e) for(int v=(e)-1;(s)<=v&&v<(e);--v)//inversion #define hforo(v, s, e) int v=(s);for(;(s)<=v&&v<(e);++v)//out declaration #define hforoi(v, s, e) int v=(e)-1; for(;(s)<=v&&v<(e);--v) #define cfor(v, s, e) hfor(v,(s),(e)+1)//closed range #define cfori(v, s, e) hfori(v,(s),(e)+1) #define cforo(v, s, e) hforo(v,(s),(e)+1) #define cforoi(v, s, e) hforoi(v,(s),(e)+1) #define rep(v,x) hfor(v,0,(x)) #define repi(v,x) hfori(v,0,(x)) #define repo(v,x) hforo(v,0,(x)) #define all(x) (x).begin(),(x).end() #define sz(x) ((int)(x).size()) #define pushb push_back #define pushf push_front #define popb pop_back #define popf pop_front #define empl emplace #define emplb emplace_back #define emplf emplace_front #define fi first #define se second #define cxp constexpr #define PQ std::priority_queue #ifndef DEBUG #pragma GCC optimize ("Ofast") auto __PRE_RUN__=(ios::sync_with_stdio(0), cin.tie(0), cout.tie(0),(cout<<fixed<<setprecision(11)), 0); #endif template<typename T> cxp T inf() { return numeric_limits<T>::max() / 2; } auto mapf(auto a, auto f){for(auto& x:a)x=f(x); return a;} int rd(int lb, int ub){static mt19937 rng(time(0)^i64(new int)); return uniform_int_distribution<int>(lb, ub-1)(rng);} int rd(int ub=inf<int>()){return rd(0,ub);} const f64 pi=acosl(-1); template<typename T> struct Xarr: public Arr<T>{ Xarr(int n=0, const T& init=T(), int offset=1):Arr<T>(n+offset, init), o(offset){} T& operator[](int i){return at(i);} T& at(int i){return Arr<T>::at(i+o);} const T& operator[](int i)const{return at(i);} const T& at(int i)const{return Arr<T>::at(i+o);} int o; }; #define endl '\n'//not interactive? #define int i64//MLE? using pint = pair<int,int>; using tint = tuple<int,int,int>; struct Line{ int tan, yic; f64 lx=-1/0.0, rx=1/0.0; int idx=0; bool operator<(const Line& r)const{return tan<r.tan;} bool operator<(const i64 x)const{return rx<x;} f64 intersectX(const Line& r)const{return (r.yic-yic)/f64(tan-r.tan);} int f(int x)const{return tan*x+yic;} }; struct StackCHT{ Arr<Line> st; int idx=1; void push(i64 tan, i64 yic){ Line f{tan, yic, 0, 1/0.0,idx++}; while(sz(st)){ f.lx=st.back().intersectX(f); if(tan==st.back().tan || f.lx<st.back().lx) st.popb(); else break; } st.pushb(f); } int i=0; i64 get(i64 x){ while(i<sz(st) and st[i].lx<=x) i++; return st[i-1].tan*x+st[i-1].yic; //int s=0, e=sz(st); //while(e-s>1){ // int m=(s+e)/2; // (x<st[m].lx?e:s)=m; //} //return st[s].tan*x + st[s].yic; } }; Xarr<int> p(100000); int dp[2][100000]; signed sav[201][100000]; void bt(int k, int i){ if(!k) return; bt(k-1,sav[k][i]-1); cout<<sav[k][i]<<' '; } signed main(){ int n,k; cin>>n>>k; int a[n]; rep(i,n) cin>>a[i]; rep(i,n) p[i]=p[i-1]+a[i]; cfor(i,1,k){ StackCHT s; s.push(p[0], -p[0]*p[0]+0); hfor(j,1,n){ dp[i%2][j]=s.get(p[j]); s.push(p[j], -p[j]*p[j]+dp[(i+1)%2][j]); sav[i][j]=s.st[s.i-1].idx; } } cout<<dp[k%2][n-1]<<endl; bt(k,n-1); return 0; }
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