Submission #180291

#	Time	Username	Problem	Language	Result	Execution time	Memory
180291		Nightmar	Money (IZhO17_money)	C++17	0 / 100	2 ms	376 KiB

money

#include <iostream>
#include <algorithm>
#include <cmath>
#include <string>
#include <cstdlib>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <cstdio>
#include <iomanip>
#include <unordered_map>

#define SWS ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define pb push_back
#define ppb pop_back
#define ft first
#define sd second
#define readf freopen("input.txt", "r", stdin)
#define writef freopen("output.txt", "w", stdout)
#define files readf; writef

using namespace std;

typedef long long ll;
typedef pair<int, int> pii;

const int Z = 999;
const int N = (int)1e6 + 228;
const int INF = (int)1e9 + 5;
const int MOD = (int)1e9 + 7;

int a[N], t[4 * N];

void update(int v, int tl, int tr, int pos) {
    if (tl == tr) {
        t[v]++;
        return;
    }
    int mid = (tl + tr) / 2;
    if (pos <= mid) update(2 * v, tl, mid, pos);
    else update(2 * v + 1, mid + 1, tr, pos);
    t[v] = t[2 * v] + t[2 * v + 1];
}

int get(int v, int tl, int tr, int l, int r) {
    if (tl >= l && tr <= r) {
        return t[v];
    }
    if (tl > r || tr < l) {
        return 0;
    }
    int mid = (tl + tr) / 2;
    return get(2 * v, tl, mid, l, r) + get(2 * v + 1, mid + 1, tr, l, r);
}

int main() {
	SWS;
	srand(time(0));
	//files;
	int n;
	cin >> n;
	vector<int> v;
	v.pb(0);
	for (int i = 1; i <= n; i++) {
        cin >> a[i];
        v.pb(a[i]);
	}
	sort(v.begin(), v.end());
	v.erase(unique(v.begin(), v.end()), v.end());
	int ans = 0;
	for (int i = 1; i <= n; i++) {
        vector<int> kek;
        int L = upper_bound(v.begin(), v.end(), a[i]) - v.begin();
        int R = lower_bound(v.begin(), v.end(), a[i]) - v.begin() - 1;
        //cout << "DEBUG : " << i << "\n";
        //cout << L << ' ' << R << endl;
        int now = lower_bound(v.begin(), v.end(), a[i]) - v.begin();
        int r = i;
        kek.pb(now);
        while (r <= n && a[r + 1] >= a[r] && !get(1, 1, v.size(), L, R)) {
            r++;
            R = lower_bound(v.begin(), v.end(), a[r]) - v.begin() - 1;
            now = lower_bound(v.begin(), v.end(), a[r]) - v.begin();
            kek.pb(now);
            //cout << L << ' ' << R << endl;
        }
        i = r;
        ans++;
        for (int q : kek) {
            update(1, 1, v.size(), q);
        }
	}
	cout << ans;
    return 0;
}

• Subtask 1: 0 / 9
• Subtask 2: 0 / 16
• Subtask 3: 0 / 20
• Subtask 4: 0 / 55