Submission #173840

#	Time	Username	Problem	Language	Result	Execution time	Memory
173840		tourist	K blocks (IZhO14_blocks)	C++14	53 / 100	5 ms	504 KiB

blocks

#include <iostream>
#include <map>
#include <vector>

using namespace std;

#define ll long long
#define sz(x) (int)x.size()
#define pii pair < int, int >
#define endl "\n"
#define METH ios::sync_with_stdio(0); cin.tie(0);
#define BEGIN cout << "BEGIN" << endl;
#define END cout << "END" << endl;

const int N = 109;
const int mod = 1e9 + 7;															/// ANOTHER HASH MOD: 228228227
const int prime = 29;																	/// ANOTHER HASH PRIME: 997
const int INF = ((long long) 0xCAFEBABE - 1e9 - 4e8);

int n, k, mx[N][N];
int a[N], ans, dp[N][N];

inline int read() {
	scanf("%d %d", &n, &k);
	for (int i = 1; i <= n; i++) {
		scanf("%d", &a[i]);
	}
	return 0;
}

void calc(int l, int k, int sum) {
	if (k == 1) {
		ans = min(ans, mx[l][n] + sum);
		return;
	}
	for (int i = l; i <= n - k + 1; i++) {
		calc(i + 1, k - 1, sum + mx[l][i]);
	}
}

inline int solve() {
	ans = INF;
	for (int i = 1; i <= n; i++) {
		for (int j = i; j <= n; j++) {
			mx[i][j] = max(mx[i][j - 1], a[j]);
		}
	}
	for (int i = 1; i <= k; i++) {
		for (int j = 1; j <= n; j++) {
			dp[j][i] = INF;
			dp[j][1] = mx[1][j];
		}
	}
	for (int i = 2; i <= k; i++) {
		for (int r = i; r <= n; r++) {
			for (int j = i; j <= r; j++) {
				dp[r][i] = min(dp[r][i], dp[j - 1][i - 1] + mx[j][r]);
			}
		}
	}

	//~ calc(1, k, 0); TODO: WHY TLE?
	cout << dp[n][k] << endl;
	return 0;
}

int main() {
	int t = 1;
	while (t--) {
		read();
		if (n >= N) {
			cout << "FUCK YOU" << endl;
			return 0;
		}
		solve();
	}
}

Compilation message (stderr)

blocks.cpp: In function 'int read()':
blocks.cpp:24:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d %d", &n, &k);
  ~~~~~^~~~~~~~~~~~~~~~~
blocks.cpp:26:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d", &a[i]);
   ~~~~~^~~~~~~~~~~~~

• Subtask 1: 14 / 14
• Subtask 2: 18 / 18
• Subtask 3: 21 / 21
• Subtask 4: 0 / 47