Submission #173684

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173684dessertion새로운 문제 (COCI19_akvizna)C++14
0 / 130
414 ms636 KiB
#include <bits/stdc++.h> using namespace std; #define pb_ push_back #define eb_ emplace_back #define mp_ make_pair //#define endl '\n' typedef long long ll; typedef unsigned long long ull; typedef pair<long,long> pll; typedef pair<int,int> pii; int N,K; long double temp=1,ftemp=1e-4,alpha=0.8; const int iterations = 5e4; long double ans = 0; vector<int> choices; mt19937 mt(time(0)); bool roll(long double p){ uniform_real_distribution<long double> dist(0,1); return dist(mt)<=p; } int ran(int a, int b){ uniform_int_distribution<int> dist(a,b); return dist(mt); } int main(){ cin.tie(0),cout.tie(0),ios::sync_with_stdio(0); cin>>N>>K; //SA while(temp>ftemp){ long double cur=0; //random setup choices.clear(); choices.pb_(1); for(int i = 1;i <K; i++){ int sel = ran(choices.back()+1,N-(K-i)+1); cur+=1.0*(sel-choices.back())/(N-(choices.back()-1)); choices.pb_(sel); } cur+=1.0*(N+1-choices.back())/(N-(choices.back()-1)); choices.pb_(N+1); ans=max(ans,cur); //here is the hill climbing part for(int t = 0; t<iterations; t++){ //we pick an index from 1 to K-1, and randomize its location int sel = ran(1,K-1); int one = choices[sel-1], two=choices[sel+1]; int nxt = ran(one+1,two-1); long double nxtcur = cur-1.0*(choices[sel]-one)/(N-(one-1))-1.0*(two-choices[sel])/(N-(choices[sel]-1)); nxtcur+=1.0*(nxt-one)/(N-(one-1))+1.0*(two-nxt)/(N-(nxt-1)); ans=max(ans,nxtcur); if(nxtcur>=cur){ cur=nxtcur; choices[sel]=nxt; } else{ if(roll(exp(-(cur-nxtcur)/temp))){ //roll succeeds, do it anyways cur=nxtcur; choices[sel]=nxt; } } } temp*=alpha; } cout.precision(10); cout<<fixed<<ans<<endl; }
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