#include <stdlib.h>
#include <stdio.h>
#include "grader.h"
#include "lang.h"
#include <bits/stdc++.h>
#define all(v) (v).begin(), (v).end()
#define sortv(v) sort(all(v))
#define uniqv(v) (v).erase(unique(all(v)), (v).end())
#define pb push_back
#define FI first
#define SE second
#define lb lower_bound
#define ub upper_bound
#define test 1
#define TEST if(test)
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
const int MOD = 1000000007; // 998244353
const int INF = 2e9;
const ll INFLL = 1e18;
const int MAX_N = 10000;
const int MAX_K = 70000;
#define SZ 100
#define LAN 56
int idx = 0;
int lan[MAX_N+10];
map<ll, int> mp;
vector<ll> v[LAN+1];
int cnt[MAX_K+1];
vector<ll> vt;
ll mx;
int c1;
int space = 0;
void add(ll x){
vt.pb(x);
}
void excerpt(int *E) {
idx++;
if(idx<=3){
for(int i=0; i<SZ; i++){
cnt[E[i]]++;
}
for(int i=0; i<MAX_K; i++){
if(cnt[i]>cnt[space]) space = i;
}
}
for(int i=0; i<SZ; i++){
ll t = (ll)E[i];
add(t);
for(int j=1; j<3; j++){
if(i+j>=SZ) break;
t = (t<<16LL)+(ll)E[i+j];
add(t);
}/*
if(E[i]==space || E[i+1]==space || E[i+2]==space) continue;
vt.pb((((ll)E[i])<<32LL)+(((ll)E[i+1])<<16LL)+(ll)E[i+2]);*/
}
sort(vt.begin(), vt.end());
vt.erase(unique(vt.begin(), vt.end()), vt.end());
mx = 0; c1 = 0;
for(int j=0; j<LAN; j++){
if(v[j].empty()) continue;
int c = 0;
int k = 0;
for(int i=0; i<vt.size(); i++){
while(k<v[j].size()-1 && v[j][k]<vt[i]){
k++;
}
c+=(v[j][k]==vt[i]);
}
if(c>c1){
c1 = c; mx = j;
}
}
int ask = mx;
lan[idx] = language(ask);
while(!vt.empty()){
v[lan[idx]].pb(vt.back()); vt.pop_back();
}
sort(v[lan[idx]].begin(), v[lan[idx]].end());
v[lan[idx]].erase(unique(v[lan[idx]].begin(), v[lan[idx]].end()), v[lan[idx]].end());
//cout<<idx<<" "<<mx<<" "<<ask<<" "<<lan[idx]<<endl;
}
Compilation message
lang.cpp: In function 'void excerpt(int*)':
lang.cpp:82:17: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
for(int i=0; i<vt.size(); i++){
~^~~~~~~~~~
lang.cpp:83:11: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
while(k<v[j].size()-1 && v[j][k]<vt[i]){
~^~~~~~~~~~~~~~
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Correct |
6240 ms |
4760 KB |
Output is correct |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Partially correct |
6394 ms |
4744 KB |
Output is partially correct - 87.74% |