# | Submission time | Handle | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
169101 | 2019-12-18T11:58:18 Z | Akashi | Mergers (JOI19_mergers) | C++14 | 12 ms | 12152 KB |
#include <bits/stdc++.h> using namespace std; int n, k; int h[500005], cul[500005], up[500005], root[500005], nr[500005], nr2[500005]; bool viz[500005], tip[500005]; int d[500005][21]; vector <int> v[500005]; priority_queue <pair <int, int> > L; void predfs(int nod = 1){ viz[nod] = 1; bool leaf = true; for(auto it : v[nod]){ if(viz[it]) continue ; leaf = false; h[it] = h[nod] + 1; predfs(it); d[it][0] = nod; } viz[nod] = 0; if(leaf) L.push({h[nod], nod}); } inline int lca(int x, int y){ if(h[x] < h[y]) swap(x, y); int dif = h[x] - h[y]; int p = 1, k = 0; while(dif){ if(dif & p) x = d[x][k], dif ^= p; p = p << 1; ++k; } if(x == y) return x; for(int t = 20; t >= 0 ; --t) if(d[x][t] != d[y][t]) x = d[x][t], y = d[y][t]; return d[x][0]; } int main() { freopen("1.in", "r", stdin); scanf("%d%d", &n, &k); int x, y; for(int i = 1; i < n ; ++i){ scanf("%d%d", &x, &y); v[x].push_back(y); v[y].push_back(x); } predfs(); for(int t = 1; t <= 20 ; ++t) for(int i = 1; i <= n ; ++i) d[i][t] = d[d[i][t - 1]][t - 1]; for(int i = 1; i <= n ; ++i){ scanf("%d", &x); cul[i] = x; if(root[x] == 0) root[x] = i; else root[x] = lca(root[x], i); } for(int i = 1; i <= n ; ++i) up[i] = root[cul[i]]; int Sol = 0, NR = 0, ad = 0; while(!L.empty()){ int nod = L.top().second; L.pop(); bool leaf = true; for(auto it : v[nod]){ if(it == d[nod][0]) continue ; leaf = false; nr[nod] += nr[it] + nr2[it]; } int TT = d[nod][0]; tip[TT] = max(tip[nod], tip[TT]); if(up[nod] != nod) up[TT] = lca(up[nod], up[TT]); else{ ++NR; if(!tip[nod]){ tip[TT] = 1, nr[nod] = 1; ++ad; } } if(nr[nod] > 1){ Sol = Sol + (nr[nod] - 1) / 2; if(nr[nod] % 2 == 0) nr2[nod] = 1; nr[nod] = 1; } if(!viz[TT] && TT != 1){ viz[TT] = 1; L.push({h[TT], TT}); } } // cerr << ad << endl; if(NR == 0) printf("0"); else{ int n1 = 0, n2 = 0; int cnt = 0; for(auto it : v[1]){ n1 += nr[it]; n2 += nr2[it]; if(nr[it]) ++cnt; } if(cnt > 1) Sol = Sol + (n1 + n2) / 2 + (n1 + n2) % 2; else Sol = Sol + n1 / 2 + n1 % 2 + n2 / 2 + n2 % 2; printf("%d", Sol); } return 0; }
Compilation message
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Incorrect | 12 ms | 12152 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Incorrect | 12 ms | 12152 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Incorrect | 12 ms | 12152 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Correct | 11 ms | 12152 KB | Output is correct |
2 | Incorrect | 11 ms | 12028 KB | Output isn't correct |
3 | Halted | 0 ms | 0 KB | - |
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Incorrect | 12 ms | 12152 KB | Output isn't correct |
2 | Halted | 0 ms | 0 KB | - |