Submission #16907

# Submission time Handle Problem Language Result Execution time Memory
16907 2015-10-24T16:49:40 Z erdemkiraz Mountain Trek Route (IZhO12_route) C++
95 / 100
191 ms 42240 KB
#include <bits/stdc++.h>

using namespace std;

#define type(x) __typeof((x).begin())
#define foreach(it, x) for(type(x) it = (x).begin(); it != (x).end(); it++)
#define end ____end

typedef long long ll;
typedef pair < int, int > ii;

const int inf = 1e9 + 333;
const ll linf = 1e18 + inf;

const int N = 2e6 + 5;

int n, k, ans;
int a[N], root[N], beg[N], end[N], val[N];

int f(int x) {
    if(x == root[x])
        return x;
    return root[x] = f(root[x]);
}

void merge(int x, int y) {
    x = f(x);
    y = f(y);
    if(val[x] != val[y])
        return;
    root[y] = x;
    beg[x] = min(beg[x], beg[y]);
    end[x] = max(end[x], end[y]);
}

int main() {

    scanf("%d %d", &n, &k);

    for(int i = 0; i < n; i++) {
        scanf("%d", a + i);
    }

    int ind = max_element(a, a + n) - a;

    for(int i = 0; i < ind; i++)
        a[i + n] = a[i];

    for(int i = 0; i < n; i++)
        a[i] = a[i + ind];

    assert(max_element(a, a + n) == a);

    set < ii > s;

    val[0] = a[0];
    root[n] = 0;

    for(int i = 1; i < n; i++) {
        int j = i;
        while(j + 1 < n and a[j + 1] == a[i])
            j++;
        for(int k = i; k <= j; k++)
            root[k] = i;
        val[i] = a[i];
        beg[i] = i;
        end[i] = j;
        int l = i - 1;
        int r = (i + 1) % n;
        if(a[i] < a[l] and a[i] < a[r]) {
            s.insert(ii(j - i + 1, i));
        }
        i = j;
    }

    while(s.size()) {
        int len = s.begin() -> first;
        if(k < len)
            break;
        int x = s.begin() -> second;
        s.erase(s.begin());
        int i = beg[x];
        int j = end[x];
        int l = val[f(i - 1)];
        int r = val[f(j + 1)];
        int p = min(k / len, min(l, r) - val[x]);
        assert(p);
        k -= p * len;
        ans += p * 2;
        val[x] += p;
        if(i - 1 > 0) {
            merge(x, i - 1);
        }
        if(j + 1 < n) {
            merge(x, j + 1);
        }
        i = beg[x];
        j = end[x];
        l = val[f(i - 1)];
        r = val[f(j + 1)];
        if(val[x] < l and val[x] < r) {
            s.insert(ii(j - i + 1, x));
        }
    }

    printf("%d\n", ans);

    return 0;

}
# Verdict Execution time Memory Grader output
1 Correct 0 ms 40788 KB Output is correct
2 Incorrect 0 ms 40788 KB Output isn't correct
3 Correct 0 ms 40788 KB Output is correct
4 Correct 0 ms 40788 KB Output is correct
5 Correct 0 ms 40788 KB Output is correct
6 Correct 0 ms 40788 KB Output is correct
7 Correct 0 ms 40788 KB Output is correct
8 Correct 0 ms 40788 KB Output is correct
9 Correct 0 ms 40788 KB Output is correct
10 Correct 17 ms 40788 KB Output is correct
11 Correct 26 ms 42240 KB Output is correct
12 Correct 23 ms 40788 KB Output is correct
13 Correct 191 ms 40788 KB Output is correct
14 Correct 173 ms 40788 KB Output is correct
15 Correct 117 ms 40788 KB Output is correct
16 Correct 167 ms 40788 KB Output is correct
17 Correct 150 ms 40788 KB Output is correct
18 Correct 156 ms 40788 KB Output is correct
19 Correct 156 ms 40788 KB Output is correct
20 Correct 137 ms 40788 KB Output is correct