답안 #16905

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
16905 2015-10-24T16:47:15 Z erdemkiraz 등산 경로 (IZhO12_route) C++
95 / 100
208 ms 42240 KB
#include <bits/stdc++.h>

using namespace std;

#define type(x) __typeof((x).begin())
#define foreach(it, x) for(type(x) it = (x).begin(); it != (x).end(); it++)
#define end ____end

typedef long long ll;
typedef pair < int, int > ii;

const int inf = 1e9 + 333;
const ll linf = 1e18 + inf;

const int N = 2e6 + 5;

int n, k, ans;
int a[N], root[N], beg[N], end[N], val[N];

int f(int x) {
    if(x == root[x])
        return x;
    return root[x] = f(root[x]);
}

void merge(int x, int y) {
    x = f(x);
    y = f(y);
    if(val[x] != val[y])
        return;
    root[y] = x;
    beg[x] = min(beg[x], beg[y]);
    end[x] = max(end[x], end[y]);
}

int main() {

    scanf("%d %d", &n, &k);

    for(int i = 0; i < n; i++) {
        scanf("%d", a + i);
    }

    int ind = max_element(a, a + n) - a;

    for(int i = 0; i < ind; i++)
        a[i + n] = a[i];

    for(int i = 0; i < n; i++)
        a[i] = a[i + ind];

    set < ii > s;

    val[0] = a[0];
    root[n] = 0;

    for(int i = 1; i < n; i++) {
        int j = i;
        while(j + 1 < n and a[j + 1] == a[i])
            j++;
        for(int k = i; k <= j; k++)
            root[k] = i;
        val[i] = a[i];
        beg[i] = i;
        end[i] = j;
        int l = i - 1;
        int r = (i + 1) % n;
        if(a[i] < a[l] and a[i] < a[r]) {
            s.insert(ii(j - i + 1, i));
        }
        i = j;
    }

    while(s.size()) {
        int len = s.begin() -> first;
        if(k < len)
            break;
        int x = s.begin() -> second;
        s.erase(s.begin());
        int i = beg[x];
        int j = end[x];
        int l = val[f(i - 1)];
        int r = val[f(j + 1)];
        int p = min(k / len, min(l, r) - val[x]);
        k -= p * len;
        ans += p * 2;
        val[x] += p;
        if(i - 1 > 0) {
            merge(x, i - 1);
        }
        if(j + 1 < n) {
            merge(x, j + 1);
        }
        x = f(x);
        i = beg[x];
        j = end[x];
        l = val[f(i - 1)];
        r = val[f(j + 1)];
        if(val[x] < l and val[x] < r) {
            s.insert(ii(j - i + 1, x));
        }
    }

    printf("%d\n", ans);

    return 0;

}
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 40788 KB Output is correct
2 Incorrect 0 ms 40788 KB Output isn't correct
3 Correct 0 ms 40788 KB Output is correct
4 Correct 0 ms 40788 KB Output is correct
5 Correct 0 ms 40788 KB Output is correct
6 Correct 0 ms 40788 KB Output is correct
7 Correct 0 ms 40788 KB Output is correct
8 Correct 0 ms 40788 KB Output is correct
9 Correct 0 ms 40788 KB Output is correct
10 Correct 19 ms 40788 KB Output is correct
11 Correct 12 ms 42240 KB Output is correct
12 Correct 0 ms 40788 KB Output is correct
13 Correct 177 ms 40788 KB Output is correct
14 Correct 190 ms 40788 KB Output is correct
15 Correct 208 ms 40788 KB Output is correct
16 Correct 160 ms 40788 KB Output is correct
17 Correct 176 ms 40788 KB Output is correct
18 Correct 167 ms 40788 KB Output is correct
19 Correct 183 ms 40788 KB Output is correct
20 Correct 112 ms 40788 KB Output is correct