Submission #168671

#	Time	Username	Problem	Language	Result	Execution time	Memory
168671		Milki	Bali Sculptures (APIO15_sculpture)	C++14	100 / 100	346 ms	32064 KiB

sculpture

#include<bits/stdc++.h>
using namespace std;

#define FOR(i, a, b) for(int i = a; i < b; ++i)
#define REP(i, n) FOR(i, 0, n)
#define _ << " " <<
#define sz(x) ((int) x.size())
#define pb(x) push_back(x)
#define TRACE(x) cerr << #x << " = " << x << endl

typedef long long ll;
typedef pair<int, int> point;

const int mod = 1e9 + 7;

int add(int x, int y) {x += y; if(x >= mod) return x - mod; return x;}
int sub(int x, int y) {x -= y; if(x < 0) return x + mod; return x;}
int mul(int x, int y) {return (ll) x * y % mod;}

const int MAXN = 2e3 + 5;

ll n, a, b, x[MAXN], prefix[MAXN], dp1[MAXN], dp[MAXN][MAXN];

int rek(int pos, int num, ll forbidden){
  if(pos < 0){
    if(num >= a && num <= b)
      return 1;
    else
      return 0;
  }
  if(dp[pos][num] != -1)
    return dp[pos][num];

  int ret = 0;
  ll sum = 0;
  for(int i = pos; i >= 0; --i){
    sum += x[i];
    if((sum & forbidden) == 0)
      ret |= rek(i - 1, num + 1, forbidden);
    if(ret)
      return dp[pos][num] = ret;
  }

  return dp[pos][num] = ret;
}

int rek_min(int pos, ll forbidden){
  if(pos < 0)
    return 0;
  if(dp1[pos] != -1)
    return dp1[pos];

  int ret = 1e5;
  ll sum = 0;
  for(int i = pos; i >= 0; --i){
    sum += x[i];
    if((sum & forbidden) == 0)
      ret = min(ret, rek_min(i - 1, forbidden) + 1);
  }
  return dp1[pos] = ret;
}

int main(){
  ios_base::sync_with_stdio(false); cin.tie(0);

  cin >> n >> a >> b;
  REP(i, n)
    cin >> x[i];

  ll forbidden = 0, sol = 0;
  for(int i = 40; i >= 0; --i){
    memset(dp1, -1, sizeof(dp1));
    memset(dp, -1, sizeof(dp));

    forbidden |= (1LL << i);
    if(n <= 100){
      if(!rek(n - 1, 0, forbidden)){
        forbidden ^= (1LL << i);
        sol |= (1LL << i);
      }
    }
    else{
      int val = rek_min(n - 1, forbidden);
      if(val > b){
        forbidden ^= (1LL << i);
        sol |= (1LL << i);
      }
    }
  }
  cout << sol;
}

• Subtask 1: 9 / 9
• Subtask 2: 16 / 16
• Subtask 3: 21 / 21
• Subtask 4: 25 / 25
• Subtask 5: 29 / 29