Submission #167670

#	Time	Username	Problem	Language	Result	Execution time	Memory
167670		Rakhmand	Money (IZhO17_money)	C++14	100 / 100	739 ms	19396 KiB

money

//
//  ROIGold.cpp
//  Main calisma
//
//  Created by Rakhman on 05/02/2019.
//  Copyright © 2019 Rakhman. All rights reserved.
//
 
#include <cstring>
#include <vector>
#include <list>
#include <map>
#include <set>
#include <deque>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <queue>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include <cassert>
#include <iterator>
 
#define ios ios_base::sync_with_stdio(0), cout.tie(0), cin.tie(0);
#define S second
#define F first
#define pb push_back
#define nl '\n'
#define NL cout << '\n';
#define EX exit(0)
#define all(s) s.begin(), s.end()
#define no_answer return cout << 0, 0;
#define FOR(i, start, finish, k) for(int i = start; i <= finish; i += k)
 
const int MXN = 1e6 + 200;
const long long MNN = 4e2 + 200;
const long long MOD = 1e9 + 7;
const long long INF = 1e18;
const int OO = 1e9 + 500;
 
typedef long long llong;
typedef unsigned long long ullong;
 
using namespace std;
 
int n, b[MXN], ans, t[4 * MXN];

int get(int v, int tl, int tr, int L, int R){
    if(L <= tl && tr <= R){
        return t[v];
    }
    if(tl > R || tr < L || L > R){
        return 0;
    }
    int tm = (tl + tr) / 2;
    return get(v * 2, tl, tm, L, R) + get(v * 2 + 1, tm + 1, tr, L, R);
}

void upd(int v, int tl, int tr, int ind, int x){
    if(tl == tr){
        t[v] = x;
        return ;
    }
    int tm = (tl + tr) / 2;
    if(ind <= tm){
        upd(v * 2, tl, tm, ind, x);
    }else{
        upd(v * 2 + 1, tm + 1, tr, ind, x);
    }
    t[v] = t[v * 2] + t[v * 2 + 1];
}

int main () {
    ios;
    cin >> n;
    for(int i = 1; i <= n; i++){
        cin >> b[i];
    }
    int l = 1, r = 1;
    while(l <= n){
        while(b[r] <= b[r + 1] && get(1, 1, 1000000, b[l] + 1, b[r + 1] - 1) == 0 && r + 1 <= n){
            r++;
        }
        ans ++;
        for(int i = l; i <= r; i++){
            upd(1, 1, 1000000, b[i], 1);
        }
        l = ++r;
    }
    cout << ans;
}
/*
 6
 3 6 4 5 1 2
 */

• Subtask 1: 9 / 9
• Subtask 2: 16 / 16
• Subtask 3: 20 / 20
• Subtask 4: 55 / 55